Answer:
1/6 ton of fish is provided during the night feeding.
Step-by-step explanation:
The fish consumed in the morning is 
tons, and the amount of fish served in the afternoon is 
greater than in the morning. This means
Let’s represent the quantity of fish given at night as 
, and if the total fish fed throughout the day equals 
, we have
By summing the numerators on the left side, we derive:
and subtracting 
from both sides allows us to isolate 
Since 
, we derive
The common denominator for the fractions is 6; hence, we write the equation in the form
and simplifying the numerators results in:
which indicates the amount of tons fed during the night feeding.
The expected loss is $1.83. Step-by-step explanation: The average value for each ticket is calculated as... ($100 + 5($20)) / 1200 = $200 / 1200 ≈ $0.1667 ≈ $0.17. Since purchasing a ticket costs $2.00, your anticipated value becomes... -$2.00 + 0.17 = -$1.83, leading to a loss of $1.83.
The question is missing some information. It should be phrased as follows:
<span><span>A container has 50 electronic components, with 10 identified as defective. If 6 components are randomly selected from the container, what is the probability that at least 4 of them are not defective? Additionally, if 8 components are drawn at random from the container, what is the probability that exactly 3 are defective?
</span>Answers
<span>Part 1. 0.02
Part 2. </span></span>0.0375<span><span>
</span>Explanation
Probability denotes the likelihood of an event occurring. It is computed as:
probability = (Number of favorable outcomes)/(Number of total outcomes)
Part 1
When 6 components are chosen, if 4 are confirmed functioning, then 2 must be defective.
P(at least 4 functional) = 4/40</span>× 2/10
= 1/10 × 1/5
= 1/50
= 0.02
Part 2
Choosing 8 components, if 3 are defective, then 5 are functioning.
P(3 defective) = 3/40 × 5/10
= 15/400
= 3/80
= 0.0375
To find the answer, subtract the total percentage of 24.65% and $48 from 1986, resulting in the final value.
