A line passes through the point (0, -1) and has a positive slope. Which of these points could that line pass through?
3 answers:
Answer:
(12, 3), (-2, -5), (1, 15)
Step-by-step explanation:
The line may intersect any point where the x-coordinate is positive and the y-coordinate exceeds -1. Such points include...
(12, 3), (1, 15)
The line can also cross any point where the x-coordinate is negative while the y-coordinate is lower than -1. That point is...
(-2, -5)
__
In the provided diagram, the lines colored green demonstrate a positive slope, while the red lines do not.
Answer:
(1, 15) (12, 3) (-2, -5)
Step-by-step explanation:
I used Desmos for this, but my answer was lost for some reason.
(-3, 1) and (5, -2) indicate a negative slope when passing through (0, -1).
In contrast, (12, 3), (1, 15), and (-2, -5) show a positive slope when they pass by (0, -1).
Hope this is helpful:)
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Answer: Children who weigh 10 pounds require 12 teaspoons, those at 15 pounds need 18 teaspoons, and for 30 pounds, it is necessary to have 36 teaspoons.
Step-by-step explanation:
We have a recommended dose of 40 mg per 2.2 pounds of weight, given in three doses throughout the day every 8 hours.
Thus, for a single pound, the daily required dosage is calculated as .
Each individual dose corresponds to of the drug.
This means for one pound, the dosage needed per dose is 6.06 ml.
Thus, for 10 pounds, the calculation is 10 x 6.06 ml = 60.6 ml
To convert ml to teaspoons, knowing that 1 teaspoon equals 5 ml, we find: (60.6 ml ÷ 5) = 12.12 ≈ 12 teaspoons.
For a weight of 15 pounds, the drug requirement is 15 x 6.06 ml = 90.9 ml.
This translates to (90.9 ml ÷ 5) = 18.18 ≈ 18 teaspoons.
For the weight of 30 pounds, it is calculated as 30 x 6.06 ml = 181.8 ml.
Converting this gives us (181.8 ml ÷ 5) = 36.36 ≈ 36 teaspoons.
Therefore, children weighing 10 pounds need 12 teaspoons, those at 15 pounds require 18 teaspoons, and those at 30 pounds need 36 teaspoons.
Answer:
The null hypothesis is stated as H₀: μ = 100
The alternative hypothesis is Hₐ: μ < 100
Evidence suggests that the average location in Wade Tract is 100
Step-by-step explanation:
We define our null hypothesis as H₀: μ = 100, where the average location of trees in the Wade Tract amounts to 100.
Our alternative hypothesis thereby is stated as Hₐ: μ < 100 at a 95% confidence level.
Proposed average location in Wade Tract is μ = 100.
The sample mean computes to = 99.74.
The standard deviation is s = 58.
The sample size n = 584.
Using the t-test formula yields the following results:
Consequently, with df = 584 -1 = 583, and α = (1 - 0.95)/2 = 0.025
We calculate = -1.65
Substituting values into the t-test formula gives t = -0.108338, producing a p-value of p = 0.4569, which exceeds α, hence we accept the null hypothesis, indicating that there is adequate statistical evidence supporting the average location of Wade Tract = 100.
Response:
Stepwise explanation:
Given the expression
x² - x - 12
First, let’s factor this expression
Refer to the attachment for simplification
x² - 4x + 3x - 12
x(x - 4) + 3(x-4)
(x + 3)(x - 4)
Consequently, 4 negative unit tiles are necessary
