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Nuetrik
9 days ago
8

A line passes through the point (0, -1) and has a positive slope. Which of these points could that line pass through?

Mathematics
3 answers:
zzz [4K]9 days ago
8 2

Answer:

(12, 3), (-2, -5), (1, 15)

Step-by-step explanation:

The line may intersect any point where the x-coordinate is positive and the y-coordinate exceeds -1. Such points include...

(12, 3), (1, 15)

The line can also cross any point where the x-coordinate is negative while the y-coordinate is lower than -1. That point is...

(-2, -5)

__

In the provided diagram, the lines colored green demonstrate a positive slope, while the red lines do not.

lawyer [4K]9 days ago
8 2

Answer:

(1, 15) (12, 3) (-2, -5)

Step-by-step explanation:

I used Desmos for this, but my answer was lost for some reason.

(-3, 1) and (5, -2) indicate a negative slope when passing through (0, -1).

In contrast, (12, 3), (1, 15), and (-2, -5) show a positive slope when they pass by (0, -1).

Hope this is helpful:)

lawyer [4K]9 days ago
1 0

None of those responses are correct!

The accurate answer is (–3, 1) (5, –2)

Wishing you a wonderful day!

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In this scenario, we start with the following expression:

58- (14) ^ 2

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Next, we have:

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The following step is to subtract the two resultant values:

58- (14) ^ 2 = -138

It is clear that the outcome of this operation is a negative value.

Answer:

The expression results in:

58- (14) ^ 2 = -138

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6a−3b=5b solve for a:b ratio plz help
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Step-by-step explanation:

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8 0
9 days ago
When jumping, a flea rapidly extends its legs, reaching a takeoff speed of 1.0 m/s over a distance of 0.50 mm . part a what is t
zzz [4035]

The flea experiences an acceleration of 1,000 m/s².

Detailed explanation

This scenario involves motion with constant acceleration.

The relevant variables include the following.

\boxed{u \ or \ v_i = initial \ velocity}

\boxed{u \ or \ v_t \ or \ v_i = terminal \ or \ final \ velocity}

\boxed{a = acceleration \ (constant)}

\boxed{d = distance \ travelled}

We know the flea attains a takeoff velocity of 1.0 m/s over a distance of 0.50 mm.

The flea starts from rest, so the initial velocity is zero. The question asks for the flea's acceleration during leg extension.

The equation we apply is:

\boxed{ \ v^2 = u^2 + 2ad \ }

  • a = acceleration (m/s²)
  • u = initial speed = 0 m/s
  • v = takeoff velocity = 1.0 m/s
  • d = displacement = 0.50 mm

First, convert 0.50 mm to meters: \boxed{0.50 \ mm = 0.50 \times 10^{-3} \ m = 5.0 \times 10^{-4} \ m}

Solution steps:

Rearrange the formula to isolate acceleration (a).

\boxed{ \ v^2 = u^2 + 2ad \ }

\boxed{ \ v^2 - u^2 = 2ad \ }

\boxed{ \ 2ad = v^2 - u^2 \ }

\boxed{ \ a = \frac{v^2 - u^2}{2d} \ }

Insert the given values into the rearranged equation.

\boxed{ \ a = \frac{(1.0)^2 - (0)^2}{2(5.0 \times 10^{-4})} \ }

\boxed{ \ a = \frac{1}{10 \times 10^{-4}} \ }

\boxed{ \ a = \frac{1}{1 \times 10^{-3}} \ }

\boxed{ \ a = 1 \times 10^{3}\ = 1,000 \ m/s^2 \ }

This yields the flea's acceleration as 1,000 m/s².

Additional resources

  1. Scientific notation: brainly.com/question/7263463
  2. Determining substance mass: brainly.com/question/4053884
  3. Conversion into cubic units: brainly.com/question/1446243

Keywords: flea, jumping, leg extension, takeoff velocity, initial speed, displacement, acceleration, constant acceleration, unit conversion

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