Answer:
y 
y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction
Explicación paso a paso:
La ecuación cuadrática que tenemos es (4y - 3)² = 72
Debemos encontrar el valor de y.
Ahora, 4y - 3 = ± 6√2
⇒ 4y = 3 ± 6√2
⇒ y
Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)
Answer:
D
Step-by-step explanation:
You should insert the provided x and y coordinates into the equations to determine which one satisfies both points.
D is valid for both:
5 = 5/4(4)
0 = 5/4(0)
Establish a proportion.
8/127=15/x
Cross multiply
8x=1,905
Divide each side by 8
x=238.125
The greatest of the actual distances is 238.125 km.
Hope this clarification helps:)
Total time taken = 9.0252 *10^12 s.
Step-by-step explanation:
Data provided:
- Distance from Earth to Alpha Centauri: 4.3 light years.
- Distance from Earth to Sirius: 8.6 light years.
- Probe speed: V = 18.03 km/s.
- 1 AU equals 1.58125 x 10^-5 light-years.
Objective:
Determine the total time the probe has been in motion from leaving Earth to reaching Sirius.
Solution:
- Journey is tracked for each destination sequentially:
Earth ------> Alpha Centauri: d_1 = 4.3 light years
Alpha Centauri ------> Earth: d_2 =4.3 light years
Earth ------> Sirius: d_3 = 8.6 light years
Sum of distances = D = 17.2 light years.
- Now, we convert the total distance into kilometers (SI units):
1 AU ----------> 1.58125 x 10^-5 light-years
x AU ----------> 17.2 light years.
- By proportions:
x = 17.2 / (1.58125 x 10^-5) = 1087747.036 AU.
Also,
1 AU ---------------------> 149597870700 m
1087747.036 AU ----> D m.
- Using proportions:
D = 1087747.036*149597870700 = 1.62725*10^17 m.
- Finally, applying the speed-distance-time formula:
Time = Distance traveled (D) / V
Time = 1.62725*10^17 / (18.03*10^3).
Final answer: Time = 9.0252 *10^12 s.
Answer:
a) 0.00019923%
b) 47.28%
Step-by-step explanation:
a) To determine the likelihood that all sockets in the sample are defective, we can use the following approach:
The first socket is among a group that has 5 defective out of 38, leading to a probability of 5/38.
The second socket is then taken from a group of 4 defective out of 37, following the selection of the first defective socket, resulting in a probability of 4/37.
Extending this logic, the chance of having all 5 defective sockets is computed as: (5/38)*(4/37)*(3/36)*(2/35)*(1/34) = 0.0000019923 = 0.00019923%.
b) Using similar reasoning as in part a, the first socket has a probability of 33/38 of not being defective as it's chosen from a set where 33 sockets are functionally sound. The next socket has a proportion of 32/37, and this continues onward.
The overall probability calculates to (33/38)*(32/37)*(31/36)*(30/35)*(29/34) = 0.4728 = 47.28%.
