int currentNumber,previousNumber = -1, countDuplicates = 0;
do {
cin >> currentNumber;
if ( previousNumber == -1) {
previousNumber = currentNumber;
}else {
if ( previousNumber == currentNumber )
countDuplicates++;
else
previousNumber = currentNumber;
}
} while(currentNumber > 0 );
cout << countDuplicates;
I have attached my code in the image below. Good luck.
ANSWER: You must use 3 print line commands here. Thus, the optimal code looks like this:
import java.util.Scanner;
public class business {
public static void main(String args[]){
Scanner stdin = new Scanner(System.in);
String Larry = stdin.nextLine();
String Curly = stdin.nextLine();
String Moe = stdin.nextLine();
System.out.println(Larry + "\t" + Curly + "\t" + Moe);
System.out.println(Larry + "\t" + Moe + "\t" + Curly);
System.out.println(Curly + "\t" + Larry + "\t" + Moe);
System.out.println(Curly + "\t" + Moe + "\t" + Larry);
System.out.println(Moe + "\t" + Larry + "\t" + Curly);
System.out.println(Moe + "\t" + Curly + "\t" + Larry);
}
}
