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SIZIF
17 days ago
11

In giraffes, long necks (N), long legs (L), dark spots (D), and the ability to digest meat (M) are all dominant traits. What pos

sible genotype could a long-necked, short-legged, light-spotted, meat-digesting giraffe have?
Biology
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An example of genetic recombination is shown in the diagram. An example of genetic recombination is shown. 2 cells are connected
vlada-n [2515]

The diagram is not provided in the question, therefore, the necessary diagram is attached below:

Answer:

conjugation

Explanation:

Conjugation refers to a reproductive process where two organisms of the same species exchange their nuclear material or DNA to create a new organism.

Binary Fission is defined as a method in which a single organism splits into two daughter cells, forming a new organism.

Transduction describes the transfer of foreign DNA into a cell facilitated by a vector.

Transformation refers to the genetic modification process whereby a cell incorporates genetic material from its environment.

Therefore, the diagram illustrates the process of "conjugation".

5 0
2 months ago
Imagine that two unlinked autosomal genes with simple dominance code in goats for size, where T is tall and t is short, and for
enyata [2506]

Answer:

(A) 0.0625

(B) 25%

Explanation:

A

With the following:

T indicates tall

t indicates short

R indicates red

r indicates tan.

When a short tan male goat mates with a tall red female goat of an unknown genotype;

Let's analyze separately;

A short tan male goat = ttrr

The female goat’s genotype is not specified but it is known to be tall and red

∴ We determine that she must be T_ R_;

the potential genotype probability of the female for each allele could be:

- T

T

or Tt- RR

or R

r

Nonetheless, from earlier discussion;

the chance that the female is Tt = \frac{1}{2}

the probability of the female being Rr = \frac{1}{2}

the probability of passing on the recessive allele 't' to offspring = \frac{1}{2}

the probability of passing on the recessive allele 'r' to offspring = \frac{1}{2}

∴ the likelihood that the pairing would yield short, tan offspring (ttrr) stands at;

= (\frac{1}{2})^{4}

= (\frac{1}{16})

= 0.0625

(B)

In pea plants, one is homozygous recessive for both traits, leading to the cross of Yy Rr × yy rr. Determine the green and round offspring percentage.

For Color, let:

Y = Yellow

y = Green

For shape, let;

R = Round

r = wrinkled

If a cross occurs between Yy Rr × yy rr. (yellow round and green wrinkled)

the ratio of green and round offspring will be;

If Yy Rr self-crosses; various traits (YR, Yr, yR, yr)

yy rr will produce (yr, yr)

                   YR                    Yr                    yR                    yr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

yr                 YyRr                 Yyrr                 yyRr                 Yyrr

                   Yellow              Yellow            Green              Green

                   Round               Wrinkled        Round              Wrinkled

                   Thus, the percentage of green and round offspring based on the above is:

=

%

\frac{2}{8}*100%=

%

\frac{1}{4}*100=

25%

7 0
2 months ago
Marge is an ace at tennis. She does not miss a ball! She has great balance and coordination. The part of Marge’s brain that help
lana [2441]

The part of the brain that enhances Marge’s tennis performance is the Pre-Frontal Cortex.

I hope this helps!

3 0
4 months ago
Read 2 more answers
Por qué las plantas de regiones lluviosas tienen en sus hojas abundantes estomas?
garik1379 [2080]

Cuando el agua es abundante (no limita), las plantas tienen la capacidad de poseer más estomas, lo que aumenta el acceso al agua (y a los iones de hidrógeno necesarios) y proporciona un mejor soporte a los tejidos herbáceos.

Espero que esta respuesta sea correcta :)

8 0
4 months ago
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