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Papessa
2 months ago
13

A standard six-sided die is rolled $6$ times. You are told that among the rolls, there was one $1,$ two $2$'s, and three $3$'s.

How many possible sequences of rolls could there have been? (For example, $3,2,3,1,3,2$ is one possible sequence.)
Mathematics
1 answer:
Leona [12.6K]2 months ago
7 0

Response:

Sequence = 120

Step-by-step breakdown:

Provided

6 rolls of a die;

Needed

Find out the potential sequence of rolls.

From the problem, we recognize that three possible outcomes arise when rolling the die;

The potential outcomes are any of the following numbers: 1, 2, or 3.

Total Rolls = 6.

Potential outcomes = 3.

We then calculate the possible rolling sequences by dividing the factorial of the given parameters as follows;

Sequence = \frac{6!}{3!}

Sequence = \frac{6 * 5 * 4* 3!}{3!}

Sequence = 6 * 5 * 4

Sequence = 120

Thus, there exist 120 possible sequences of rolls.

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