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sertanlavr
9 days ago
10

A small coffee shop sells freshly squeezed juices in a refrigerated unit with slots where juice is displayed. These slots are ca

lled facings. The manager of the coffee shop suspects that the distribution of juice sales is different than the distribution of facings for each type of juice, so the manager records the sales of each juice over a two-week period. The proportion of facings and the sales for each type of juice are shown in the tables.
Juice Mango Orange Apple Pineapple Grapefruit Grape
Proportion of Facings 0.1875 0.250 0.250 0.125 0.125 0.0625
Juice Mango Orange Apple Pineapple Grapefruit Grape
Observed Number of Sales 23 35 46 12 10 5
(a) Construct a single bar chart that contains both the expected proportion of sales based on the proportion of facings and the observed proportion of sales for each type of juice.

BoldItalicUnderline

Mathematics
1 answer:
AnnZ [3.8K]9 days ago
8 0

Answer: please refer to the attached image

Step-by-step explanation:

Provided data:

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 0.1875 0.250 0.250 0.125 0.125 0.0625

To visualize the proportion on the graph, we multiply by 100; thus,

Juice Mango Orange Apple Pineapple Grapefruit Grape

Proportion of Facings 18.75 2.50 2.50 1.25 1.25 6.25

Juice Mango Orange Apple Pineapple Grapefruit Grape

Observed Number of Sales 23 35 46 12 10 5

(a) Create a unified bar chart that includes both the anticipated sales proportion based on the facings' ratio and the actual sales proportion for each juice.

<pUtilizing an online bar chart tool, the blue bars represent the proportion of facings while the red bars depict the observed sales values for each juice type provided.

From the chart, it is clearly observable that the facing distribution does not match the sales distribution of the juices.

The produced bar chart is attached below.

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Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [3916]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
6 days ago
What is the nearest ten thousand, the population of Vermont was estimated to be about 620,000 in 2008 . What might have been the
AnnZ [3877]

Answer:

The exact population of Vermont in 2008 could have been around 618,000

Step-by-step explanation:

* Here's how rounding to the nearest ten thousand works:

- Numbers ending with the last four digits between 0001 and 4999 are rounded down to the nearest lower multiple of ten thousand

- Example: 83,525 rounds down to 80,000.

- If the last four digits are 5000 or above, round up to the next higher ten thousand

- Example: 58,988 rounds up to 60,000

* Applying this rule to the problem given:

Since the rounded population is 620,000 to the nearest ten thousand, the actual population could be any value with the last four digits from 0001 to 4999 (like 618,000) or from 5000 upwards (like 624,000).

Therefore, 618,000 might represent the actual population of Vermont in 2008

6 0
15 days ago
Sanjit drives the 45 km distance between York and Leeds he then drives a further 42 km from Leeds to Blackpool
Leona [4166]

The average speed for his entire journey from York to Blackpool is about 61.41 km/h.

Here’s a breakdown of how we arrive at this:

\text{ The average speed}=\frac{\text{Total distance covered}}{\text{Total time taken}}

The distance he travelled from York to Leeds is 45 km,

and the speed during that section was 54 km/h.

Therefore, the time taken to travel from York to Leeds is 45/54 hours (since Time = Distance/Speed).

Next, the distance from Leeds to Blackpool is 42 km,

and the time for that leg of the journey is 35 minutes, which is 35/60 hours.

This leads to the total duration for his trip as

=\frac{45}{54}+\frac{35}{60}=\frac{450+315}{540}=\frac{765}{540}=\frac{17}{12} hours.

The cumulative distance covered equals 45 + 42 = 87 km.

Thus, his average speed is calculated as:

=\frac{87}{17/12}= \frac{12\times 87}{17}=\frac{1044}{17}=61.4117647\approx 61.41\text{ km per hour}

3 0
4 days ago
Read 2 more answers
(HELP!!!) Gustavo invests £520 for 6 years in a bank account paying simple interest. At the end of 6 years, the amount in the ba
Inessa [3907]
629.20 divided by 520 equals 1.21
Power of 6V1.21 equals 1.0323
Interest rate is 3.23
7 0
7 days ago
Jerome is a co-owner of a small company and received 1\3 of the companies?profits this year. What were the company?s overall pro
Inessa [3907]
Jerome's share of the total profit amounts to one-third. To determine the overall profit of the company, multiply his profit by 3.
If he earned $150,000, the calculation would be:
150,000 × 3 = $450,000

So, the total profit is $450,000.

The dot simply represents multiplication.
4 0
12 days ago
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