The result is 8. Vanilla makes up 26%, which translates to 13 from 50, whereas chocolate at 42% gives 21. The difference is 21-13=8.
The likelihood of observing a sample mean that is less than 18 hours is 0.0082. \nTo evaluate this probability, we calculate the z-score for a sample mean of 18. Accordingly, the probability of getting a sample mean below 18 hours becomes P(z<z(18)). \nThe z-score is calculated as follows: \nz(18) = [(X - M) / s] where: \n- X is the sample mean (18 hours) \n- M is the average hours dentists devote weekly to fillings (20 hours) \n- s is the standard deviation (10 hours) \n- N is the sample size (144) \nSubstituting the numbers leads to: \nz(18) = [(18 - 20) / (10/sqrt(144))]. Using the z-table, we find that P(z<z(18)) is 0.0082.
500Step-by-step explanation:I assume each digit ranges from 0 to 9. Additionally, there are 5 letters.10 * 5 * 10 = 500
65^2-16^2=63^2, which means the answer is 63.
