Answer:
Total bandwidth: 8 kHz
Explanation:
Data provided:
Transmitter frequency: 3.9 MHz
Modulation up to: 4 kHz
Solution:
For the upper side frequencies:
Upper side frequencies = 3.9 × + 4 × 10³
Upper side frequencies = 3.904 MHz
For the lower side frequencies:
Lower side frequencies = 3.9 × - 4 × 10³
Lower side frequencies = 3.896 MHz
Consequently, the total bandwidth is computed as:
Total bandwidth = upper side frequencies - lower side frequencies
Total bandwidth = 8 kHz
Response:
The cutting speed is calculated at 365.71 m/min
Clarification:
Given parameters include
diameter D = 250 mm
length L = 625 mm
Feed f = 0.30 mm/rev
cut depth = 2.5 mm
n = 0.25
C = 700
To find
the cutting speed that ensures the tool life coincides with the cutting time for the three parts
The formula for cutting time is given as
Tc =
....................1where D refers to diameter, L refers to length and f refers to feed while V represents speed
Tc =
Tc =
Given the tool life is expressed as
T = 3 × Tc............................2
where T denotes tool life and Tc is the cutting duration
Calculating tool life by substituting values into equation 2 yields
T = 3 ×
This yields V = 365.71
Thus, the cutting speed calculates to 365.71 m/min