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Lisa
2 months ago
5

Write a sequence of statements that create a file named "greeting" and write a single line consisting of "Hello, World!" to that

file. Make sure that the line has been flushed to the file and that any system resources used during the course of running these statements have been released.
Computers and Technology
1 answer:
Amiraneli [1K]2 months ago
4 0

Answer:

The following code is written in Python 3:

  1. outfile = open("greeting.txt", "w")
  2. outfile.write("Hello World")
  3. outfile.close()

Explanation:

To generate a simple text file in Python, the built-in function open() is utilized. This function requires two arguments,

  1. the name of the file and
  2. a single keyword "w", which stands for "write". This indicates to the program to create the file if it doesn't already exist.

The line open("greeting.txt", "w") will create a file named "greeting.txt" (Line 1)

To add content to greeting.txt, the write() method is employed. Simply pass the content string as an argument to the write() method. (Line 2)

Finally, the close() method is called on the opened file, outfile. This releases system resources associated with outfile.

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A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen
Natasha_Volkova [1026]

Answer:

C3H8

Explanation:

Step 1:

Relevant details from the question are noted below:

Mass of the alkane is 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Convert to the appropriate units.

For Volume:

1000mL = 1L

So, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature in Kelvin = Temperature in Celsius + 273

Temperature in Celsius = 28°C

Temperature in Kelvin = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

So, 741 mmHg = 741/760 = 0.975atm

Step 3:

Calculate the moles of the alkane.

The moles of the alkane can be found using the ideal gas equation, presented below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of moles (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 moles

Step 4:

Calculate the alkane’s molar mass.

Mass of alkane = 1.17g

Number of moles = 0.0266moles

Molar Mass =?

Number of moles = Mass/Molar Mass

Molar Mass = Mass/Number of moles

Molar Mass of alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determine the molecular formula of the alkane.

This is based on:

The general formula for alkanes is CnH2n+2

To find the molecular formula, we start with n = 1, 2, 3, etc., until we find the molar mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

It can be observed that for n equal to 3, the molar mass is 44g/mol.

Thus, the molecular formula of the alkane is C3H8.

7 0
2 months ago
Write a code segment to change the name of the Thing object something such that the new name consists of the old name with one c
oksian1 [950]

Answer:

import random

def name_change( name: list ) -> list :

   choice = random.choice( name )

   choice_index = name.index( choice )

   name.pop( choice_index )

   return name

Explanation:

The provided Python code utilizes the random library to randomly select an item from a list within the function "name_change". The index of the selected item is then retrieved from the list and removed from the original list called "name", with the modified name subsequently returned.

To activate the function, assign it to a variable, supply a list (it must be a list) as its argument, and then express the result.

6 0
3 months ago
In mathematics, the factorial of a positive integer n, denoted as n! , is the product of all positive integers less than or equa
oksian1 [950]
public static int factorial(int n) { if (n >= 1 && n <=12) { if (n == 1) return 1; else return n * factorial(n - 1); } else return -1; } Explanation: The factorial method takes a single integer n as input. It checks if n is within the range of 1 to 12. If it is, it further checks if n equals 1. If it is indeed 1, it returns 1 as the factorial. Otherwise, it recursively calls itself with n decreased by 1, multiplying the result by n. If n is outside this range, the method returns -1 indicating the input is invalid.
6 0
2 months ago
Read 2 more answers
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