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3 months ago

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1. Pada pertandingan sepak bola yang dilaksanakan sebanyak 20 kali, ternyata Tim Indonesia menang 12 kali, seri 6 kali dan kalah

2 kali. Berapakah peluang Tim Indonesia akan menang?

1 answer:

zzz [12.3K]3 months ago

7 0

Jawaban:

n(menang) = 6

n(seluruh) = 20

P(menang) = n(menang)/n(seluruh) = 6/20 = 3/10 atau 0,3 atau 30%

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Answer: OPTION B

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As a consequence, considering this, the transformation takes the following structure:

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Answer: Initially, he had 27 sweets.

Step-by-step explanation: The most logical approach is to work backwards from what remained after the third day to the start of the first day.

On the third day, he consumed one-third of his sweets and was left with 8. If we let the total sweets on day three be denoted as a, then one-third of a equals what he ate and the two-thirds left equals 8, giving us:

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Let the sweets on day two be represented as b. If he consumed one-third of b and was left with 12, we have the same structure; hence:

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Cross-multiplying gives:

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3 months ago

Which expression is equivalent to (StartFraction 4 m n Over m Superscript negative 2 Baseline n Superscript 6 Baseline EndFracti

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Which expression is equivalent to $\frac{4mn}{m^{-2}n^6}$ . Assuming $m \neq 0; n\neq 0$

Answer:

$\frac{4m^3}{n^5}$

Step-by-step explanation:

Given

$\frac{4mn}{m^{-2}n^6}$

Required:

Simplify

To achieve simplification, we begin by dividing each function individually

$\frac{4mn}{m^{-2}n^6} = \frac{4m}{m^{-2}} * \frac{n}{n^6}$

According to the properties of indices

$\frac{a^x}{a^y} = a^{x-y}$

Thus, the aforementioned expression can be restated similarly

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{1-(-2)} * n^{1-6}$

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From the indices laws

$a^{-x} = \frac{1}{a^x}$

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$\frac{4m}{m^{-2}} * \frac{n}{n^6} = 4m^{3} * \frac{1}{n^5}$

$\frac{4m}{m^{-2}} * \frac{n}{n^6} = \frac{4m^3}{n^5}$

Therefore, $\frac{4mn}{m^{-2}n^6}$ can be regarded as $\frac{4m^3}{n^5}$

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