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1 month ago

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It is recommended that adults consume at least 1,000 mg of calcium every day. One ounce of whole milk contains about 25 mg of ca

lcium, and one ounce of cheddar cheese contains 200 mg of calcium. If a person meets the recommendation by consuming x ounces of whole milk and y ounces of cheddar cheese, then 25x + 2007 2 1,000. Which choice give an amount of milk and cheese tha a person could consume to meet the recommendation?
A. 50 oz milk and 2 oz cheese
B. O oz milk and 4.5 oz cheese
C. 10 oz milk and 3 oz cheese
D. 39 oz milk and 0 oz cheese

1 answer:

Zina [12.3K]1 month ago

3 0

Given:

It's advisable for adults to ingest no less than 1,000 mg of calcium daily.

$25x+200y\geq 1000$

Step-by-step explanation:

Let x represent the amount of milk in ounces, and y the amount of cheddar cheese in ounces.

A person fulfills the daily requirement if

$25x+200y\geq 1000$

For option A,

Substituting x=50 and y=2 into the provided inequality.

$25(50)+200(2)\geq 1000$

$1250+400\geq 1000$

$1650\geq 1000$

This statement is true. Hence, option A is correct.

Similarly,

For option B,

Substituting x=0 and y=4.5 into the provided inequality.

$25(0)+200(4.5)\geq 1000$

$900\geq 1000$

This statement is false. Hence, option B is incorrect.

For option C,

Substituting x=10 and y=3 into the provided inequality.

$25(10)+200(3)\geq 1000$

$850\geq 1000$

This statement is false. Hence, option C is incorrect.

For option D,

Substituting x=39 and y=0 into the provided inequality.

$25(39)+200(0)\geq 1000$

$975\geq 1000$

This statement is false. Hence, option D is incorrect.

The only correct option is A.

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Detailed solution:

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