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tino4ka555
7 days ago
13

Wang Yong owes the bank $8500. To repay the debt, he paid a fixed amount back to the bank each month. After 12 months, his remai

ning debt was $6460. How much did Wang Yong pay each month?
Mathematics
1 answer:
AnnZ [3.8K]7 days ago
7 0
The monthly payment amounts to 538.3

$6450 divided by 12 (months)
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Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,
Svet_ta [4321]

Answer:

Here’s the response provided

Step-by-step explanation:

Referring to the flask diagram, the diameter of the cylinder measures 1 inch and its height (h) is 3 inches. Thus, the radius of the cylinder (r) = diameter / 2 = 1/2 = 0.5 inch

The volume of the cylinder can be calculated as πr²h = π(0.5)² × 3 = 2.36 in³

As for the sphere, its diameter is 4.5 in. Hence, the radius of the sphere R = diameter / 2 = 4.5/2 = 2.25 in

The volume of the sphere is calculated as 4/3 (πR³) = 4/3 × π × 2.25³ = 47.71 in³

The total volume of the flask = Volume of the cylinder  + Volume of the sphere = 2.36 + 47.71 = 50.07 in³

<pWhen the cylinder and the sphere are expanded by a scale factor of 2, the height (h') of the cylinder becomes 3/2 = 1.5 inches and the radius (r') becomes 0.5/2 = 0.025 inches.

The new volume for the cylinder = πr'²h' = π(0.25)² × 1.5 = 0.29 in³

For the sphere, the new radius is R' = 2.25 / 2 = 1.125 in.

The new volume of the sphere = 4/3 (πR'³) = 4/3 × π × 1.125³ = 5.96 in³

Thus, the new volume of the flask = The new volume of the cylinder  + The new volume of the sphere = 0.29 + 5.96 = 6.25 in³

<pThe ratio of the new volume to the original volume = New Volume of the flask / Volume of the flask = 6.25 / 50.07 = 1/8 = 0.125<pThe resulting volume will thus be 0.125 times the original volume

6 0
4 days ago
Express x in term of y:x/7+2y=6​
AnnZ [3877]

Answer:

You need to multiply the denorminator both sides in order to form x note the subject:

\frac{x}{7 + 2y} = 6

x = 6(7 + 2y)

8 0
12 days ago
Which are the solutions of x2 = –5x + 8? StartFraction negative 5 minus StartRoot 57 EndRoot Over 2 EndFraction comma StartFract
tester [3916]

Answer:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Detailed solution:

Given:

The problem to solve is:

x^2=-5x+8

Convert the equation into the standard quadratic form ax^2+bx +c =0, where a,\ b,\ and\ c represent constants.

So, by adding 5x-8 to both sides, we get:

x^2+5x-8=0

Note that a=1,b=5,c=-8.

The roots of this quadratic are found by applying the quadratic formula given as:

x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a=1,b=5,c=-8 into the formula and calculate for x.

x=\frac{-5\pm \sqrt{5^2-4(1)(-8)}}{2(1)}\\x=\frac{-5\pm \sqrt{25+32}}{2}\\x=\frac{-5\pm \sqrt{57}}{2}\\\\\\\therefore x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

Hence, the roots are:

x=\frac{-5-\sqrt{57} }{2}\ or\ x=\frac{-5+\sqrt{57} }{2}

4 0
14 days ago
Read 2 more answers
Which statement is true about the discontinuities of the function f(x)? F (x) = StartFraction x minus 5 Over 3 x squared minus 1
AnnZ [3877]

Question:

Which statement is accurate concerning the function’s discontinuities f(x) = \frac{x-5}{3x^2-17x-28}

A) There are gaps at x = 7 and.

B) Asymptotes exist at x = 7 and.

C) Asymptotes exist at x = –7 and.

D) Gaps are present at (–7, 0) and.

Answer:

B) Asymptotes exist at x = 7 and (x = \frac{-4}{3})

Step-by-step explanation:

Given:

f(x) = \frac{x-5}{3x^2-17x-28}

Goal:

Identify the correct statement

f(x) = \frac{x-5}{3x^2-17x-28}

We need to factor the denominator first.

f(x) = \frac{x-5}{(3x+4)(x-7)}

To express x in terms of (3x+4) and (x-7):

3x + 4 =

3x = -4

Divide both sides by 3:

x = \frac{-4}{3}

x - 7

x = 7

Next, evaluate the limit when (x = \frac{-4}{3}) and at (x = 7)

lim f(x) as (x = \frac{-4}{3}) = ±∞

lim f(x) as (x=7) = ±∞

Since both scenarios result in the denominator approaching zero, they represent asymptotes.

Thus, asymptotes are found at (x = \frac{-4}{3}) and x=7

Option B is determined to be correct

6 0
3 days ago
Two parallel lines are crossed by a transversal. What is the value of x ?
tester [3916]

Answer:

Angle x = angle 115°.

Step-by-step explanation:

Given: We have two parallel lines intersected by a transversal.

To find: The value of x.

Solution: Since two parallel lines are intersected by a transversal, corresponding angles, which are a pair lying on the same side of the transversal—one being on the interior and the other on the exterior—are equal.

Thus, angle x = angle 115, being corresponding angles.

Therefore, angle x = angle 115.

4 0
5 days ago
Read 2 more answers
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