. The cost of 2 pizzas and 1 burger is ₹ 450. Write a linear equation for this situation and draw its graph.​

Utilizing the normal distribution and the central limit theorem, there's a 0.0284 or 2.84% chance of observing a sample mean mass of 695g or less.

Health inspector visits once a week.
Fire inspector comes every 12 days.

a) health inspector fire inspector.
day 7.                    day 12.   
day 14.                    day 24.
day 21.                    day 36.
day 28.                    day 48.
day 35.                    day 60.

b) 12 x 7 = 84.

Both will coincide on day 84.

Answer:

4.0921 reflects the logarithm of the equilibrium constant.

Step-by-step explanation:

; ​E​° = - 0.41 V

; E° = 0.80 V

Iron has a negative reduction potential, indicating its tendency to lose electrons and undergo oxidation, and thus it will be at the anode.

=Reduction potential of cathode - Reduction potential of anode

; ​E​° = - 0.41 V

; E° = 0.80 V

Net reaction:

n = 2

To determine the equilibrium constant, we utilize the correlation with Gibbs free energy, as follows:

and,

Aligning these two equations yields:

where,

n = electrons transferred = 2

F = Faraday's constant = 96500 C

= standard electrode potential of the cell = 1.21 V

R = gas constant = 8.314 J/K.mol

T = reaction temperature =

Substituting values into the equation, we arrive at:

4.0921 represents the logarithm of the equilibrium constant.

Answer:

a) Ann has a 1/3 chance of winning in the first round

b) The chance of Ann winning for the first time in the fourth round is 8/81

c) The probability that Ann's first win occurs after the fourth round is 16/81

Step-by-step explanation:

a) Each strategy is played with a probability of 1/3. Given any strategy, there’s a 1/3 chance that Bill will choose the strategy that allows Ann to win. Consequently, the probability of Ann securing a victory in the first round (or any round) is

1/3 * 1/3 + 1/3 * 1/3 + 1/3 * 1/3 = 1/9 + 1/9 + 1/9 = 1/3.

Thus, the likelihood of Ann winning the initial round is 1/3.

b) The chances of Ann winning a round stand at 1/3; therefore, her chances of not winning are 2/3. This must happen three times before her first victory. Thus, the probability that Ann's first win occurs in the fourth round is

(2/3)³ * 1/3 = 8/81.

c) The first victory happens after the fourth round if she remains unsuccessful in the first four rounds, translating to a possibility of (2/3)⁴ = 16/81.

To tackle this problem, you can use the same method from the prior situation.

Option 1: 2/(1/16 + 1/65) = 25.7 mpg

Option 2: 2/(1/14 + 1/85) = 24.0 mpg

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Like before, enhancing the least efficient vehicle yields the best outcome.