Margy is trying to improve her cardio endurance by performing an exercise in which she alternates walking and running 100.0 m ea

Margy begins at a speed of 1.4 m/s and accelerates at 0.2 m/s^2 over a 100.0m distance. The velocity during this interval can be expressed as v(t) = 1.4 + 0.2 *t, indicating the speed as time progresses. Another useful equation is:
x(t) = Xi + Vi*t + 1/2at^2
where Xi denotes the initial position, set to 0 here,
Vi represents the starting speed of 1.4 m/s,
and a is the acceleration of 0.2 m/s^2.
The total distance covered is 100m.
Thus, we can set up the equation 100 = 0 + 1.4*t + 1/2 * 0.2 * t^2
Now, solve for t and then substitute back into v=1.4+0.2*t to determine the final velocity.

To solve this problem, apply the formulas:
s = Vo*t + (1/2)*a*t^2
Vf = Vo + at
The provided values include:
Vf = final velocity =?
Vo = initial velocity = 1.4 m/s
a = acceleration = 0.20 m/s^2
s = displacement = 100m
Now perform the following calculations:
<span>100 = 1.4t + (1/2)*0.2*t^2
</span>t = 25.388s
and
Vf = 1.4 + 0.2(25.388)
Vf = 6.5 m/s
Thus, the sought answer is 6.5 m/s