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Allisa
3 months ago
7

Jackson is flying at a constant rate of 500 mph from New York, New York, to Austin, Texas, which is a distance of 1,750 miles. I

f the distance Jackson has traveled in miles is a function of time in hours he has been flying, determine an appropriate domain and range for this problem situation.

Mathematics
1 answer:
Inessa [12.5K]3 months ago
6 0
A visual representation of the solution to the problem was provided.

You might be interested in
a plane is passed through a parallelepiped, cutting all the lateral edges and forming a right section which is a square. If the
Svet_ta [12734]
The question already provides multiple pieces of information. By utilizing the details given, the answer can be easily arrived at.
Lateral area of the solid = 216 cm^2
Lateral edge of the solid = 9 cm
Let's denote the length of one side of the section as x
Thus,
216 = 4s * 9
216 = 36s
s = 6
From this deduction, it is evident that the length of one side of the section is 6 cm. I trust this answer has been helpful for you.
3 0
2 months ago
Susan and ronald dugan agreed upon the price of 256,000 for their new home. They plan to make 30 percent down payment and financ
babunello [11817]

Answer:

The total amount due for purchasing the new home comes to $838,014.72

Step-by-step explanation:

Provided are:

The price set for the new house is $256,000

The down payment intended is 30% of the house price

Therefore, the down payment totals =  30% of $256,000

i.e. The down payment equals to \dfrac{30}{100} × 256000

Or, The down payment price computes to $76,800

Next, the remaining amount is financed

Thus, The financing amount is p = $256000 - $76800 = $179,200

The interest rate applied = r = 7.5%

The duration for financing = t = 20 years

Let The Amount after 20 years of financing be $A

Let the overall sum payable for the new home = $B

Using Compound Interest

Amount = Principal × (1+\dfrac{\textrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\textrm r}{100})^{\textrm t}

Or, A = $179,200 × (1+\dfrac{\textrm 7.5}{100})^{\textrm 20}

Or, A = $179,200 × (1.075)^{\textrm 20}

Or, A = $179,200 × 4.24785

∴  A = $761,214.72

Therefore,The Amount to be paid after 20 years of financing = A = $761,214.72

Subsequently

The final amount to be paid for the new home = Down payment total + The Amount to be paid after 20 years of financing

Or, B = $76,800 + A

Or, B = $76,800 + $761,214.72

Or, B = $838,014.72

Therefore, the overall amount due for the new home is rounded to $838,014.72  Answer

7 0
2 months ago
Thirty-four college students were asked how much money they spent on textbooks for the current semester. Their responses are sho
lawyer [12517]

Answer:

(a) The data point that is considered an outlier is $810.

(b) The distribution regarding expenditures on textbooks among the 34 students is right skewed.

Step-by-step explanation:

The provided data regarding how much 34 college students spent on textbooks is:

S = {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280, 290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

(a)

An outlier is defined as a value significantly different from the rest of the dataset, being either excessively high or low.

A widely-used approach for identifying outliers involves:

  • Identifying values that fall below Q₁ - 1.5 IQR as outliers.
  • Identifying values that exceed Q₃ + 1.5 IQR as outliers.

In our case,

Q₁ = first quartile

Q₃ = third quartile

IQR = Interquartile range = Q₃ - Q₁.

The first quartile value corresponds to more than 25% of the data points. It can be found by examining the median of the first half of the data.

Calculate the first quartile with the set below:

Initial half of data: {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280}

This subset contains 17 values.

The median in an odd-sized dataset is the central point.

The central value here is: 180

Thus, the first quartile is Q₁ = 180.

The third quartile value corresponds to more than 75% of the data points.

We determine the third quartile from the second half of the data:

Final half of data: {290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

<pthis subset="" also="" consists="" of="" values.="">

The median of an odd dataset serves as the middle value.

The central point is: 390

Hence, the third quartile is Q₃ = 390.

Calculate the interquartile range as follows:

IQR = Q₃ - Q₁

      = 390 - 180

      = 210

Next, we compute the value of [Q₁ - 1.5 IQR]:

Q_{1}-1.5\ IQR =180-(1.5\times 210)=-135

And then we compute [Q₃ + 1.5 IQR]:

Q_{3}+1.5\ IQR =390+(1.5\times 210)=705

There are no values below [Q₁ - 1.5 IQR]. However, one value exceeds [Q₃ + 1.5 IQR].

X = 810 > [Q₃ + 1.5 IQR] = 705

Consequently, the outlier identified within the dataset is $810.

(b)

A distribution is classified as positively skewed or right-skewed when the majority of the data congregates on the lower end of the spectrum.

The stem plot indicates that most of the data values are concentrated on the left side, confirming that the distribution is indeed right skewed.

</pthis>
5 0
3 months ago
HCF of 522, 1624, 1276​
zzz [12365]

Answer and Detailed Explanation:

We~ need ~to ~find ~the~ HCF~ of ~1624, 522 ~and~ 1276~so~in~order~to~find~this we~will~have~to~use~prime~factorization.

→ The prime factorization of 1624  is:

= 2 × 2 × 2 × 7 × 29

→ The prime factorization of 522  is:

= 2 × 3 × 3 × 29

→ The prime factorization of 1276  is:

= 2 × 2 × 29 × 11

→ HCF~of~1624, 522, 1276~is:  =2× 29=58

8 0
3 months ago
Read 2 more answers
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