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ladessa
2 months ago
15

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling. Abha collected 178

more cans than Shane did. Write an inequality to determine the number of cans, S, that Shane could have collected.
Mathematics
1 answer:
Zina [12.3K]2 months ago
4 0

Answer:

2x+178\geq 2000

Step-by-step explanation:

Let the number of cans collected by Shane be x.

Thus, the number of cans collected by Abha is x + 178.

Given that a minimum of 2000 cans is required to be collected.

Therefore, we have the inequality,[ [TAG_19]]

Total cans by Shane + Total cans by Abha ≥ 2000.

That is, x+(x+178)\geq 2000

Thus, the necessary inequality is 2x+178\geq 2000.

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The Green family is a family of six people. They have used 4,885.78 gallons of water so far this month. They cannot exceed 9,750
Zina [12379]
The inequality is  x ≤ (9750.05 - 4885.78)/6. This represents the amount of water a single family member may utilize for the remainder of the month.
3 0
1 month ago
Read 2 more answers
Assume that x and y are both differentiable functions of t and find the required values of dy/dt and dx/dt. x2 + y2 = 25 (a) Fin
Zina [12379]

Answer:

(a) \frac{dy}{dt}=-3\frac{3}{4}

(b) \frac{dx}{dt}=3\frac{3}{4}

Step-by-step explanation:

x^{2} +y^{2}=25

Calculate \frac{d}{dt} for each term.

\frac{d}{dt}(x^{2})+\frac{d}{dt}(y^{2})=\frac{d}{dt}(25)\\\\(\frac{d}{dx}(x^{2})*\frac{dx}{dt}) +(\frac{d}{dy}(y^{2})*\frac{dy}{dt})=\frac{d}{dt}(25)\\\\2x\frac{dx}{dt} +2y\frac{dy}{dt} = 0\\\\

For Question a

2y\frac{dy}{dt}=-2x\frac{dx}{dt}\\\\\frac{dy}{dt}=\frac{-2x\frac{dx}{dt}}{2y} \\\\\frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

With x = 3, y = 4, and dx/dt = 5.

\frac{dy}{dt}=-\frac{3}{4}*5=-\frac{15}{4}\\ \\\frac{dy}{dt}=-3\frac{3}{4}

For Question b

2x\frac{dx}{dt}=-2y\frac{dy}{dt}\\\\\frac{dx}{dt}=\frac{-2y\frac{dy}{dt}}{2x} \\\\\frac{dx}{dt}=-\frac{y}{x}\frac{dy}{dt}

Given x = 4, y = 3, and dx/dt = -5.

\frac{dx}{dt}=-\frac{3}{4}*-5=\frac{15}{4}\\ \\\frac{dx}{dt}=3\frac{3}{4}

5 0
2 months ago
A child has a box full of colored building blocks. She will choose one block without looking. The odds against choosing a blue b
tester [12383]

(a) A child possesses a container filled with colored building blocks. She will select one block without looking. The odds against selecting a blue block are 4/7. What is the probability of selecting a blue block?

Answer:

The likelihood of selecting a blue block is 7/11.

Step-by-step explanation:

To find the probability of selecting a blue block,

Odds:

The odds of a given event is the ratio of the probability of that event occurring to the probability of its absence. This means it compares favorable outcomes to those that are unfavorably likely.

The odds of not selecting a blue block being 4/7 means that out of 11 scenarios, there will be 4 occasions when the block is not blue, and 7 when it is blue.

Thus, the probability of not selecting the blue block is 4/11.

Probability of selecting the blue block is the complement of 4/11 which equals 7/11.

(b) Amanda plays a role-playing game with her friends. She will roll dice to decide if her character accesses a treasure chest. The chance of her character unlocking this chest is 13/20. Determine the odds in favor of her character unlocking the treasure chest.

Answer:

The odds in favor of her character unlocking the treasure chest equal 13/7.

Step-by-step explanation:

The probability of Amanda's character unlocking the treasure chest is given as 13/20.

This indicates that in a total of 20 chances, there will be 13 instances where the character successfully opens the treasure chest, while the remaining 7 times, they will not succeed.

Favorable outcomes: 13

Unfavorable outcomes: 7

Consequently, the odds in favor of her character unlocking the treasure chest are 13/7.

7 0
2 months ago
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