Answer and explanation:
Algebra revolves around the fundamental idea of using letters known as variables to represent quantities, which allows for solving for unknown values. Essentially, algebra involves transitioning from what is known to what is unknown to ascertain those unknown results. For instance, if we know a specific item was purchased twice but we're unsure of its price, we can denote this unknown price as 2a or 2p, depending on the selected variable. If the total spending for those items is, say, $50, we can set up the equation 2a = $50, which leads us to find that the cost per item is $25.
Algebra can also manifest itself in expressions, commonly referred to as algebraic expressions, which can be incorporated into equations, such as the previously mentioned 2a = $50. These expressions may take forms like 2a + 3b, where a and b designate the costs of different products that were acquired in quantities of 2 and 3, respectively.
Response:
j = 21 and n = 14
Step-by-step breakdown:
We start with the equations:
6j + n/3 = 134
j/3 + n = 31
54j + 3n = 1206
j + 3n = 93
53j = 1113
j = 21
(21)/3 + n = 31
7 + n = 31
n = 14
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