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Ivan
7 days ago
13

Decide whether the set A of positive integers divisible by 17 and B the set of positive integers

Mathematics
1 answer:
Inessa [3.9K]7 days ago
4 0

Answer:

  • Yes; refer to the question's clarification and the detailed answer below for more information.

Explanation:

Sets are in bijection if there is a bijective function connecting them.

This implies that the question can be interpreted as: can sets A and B be related via a bijective function?

A bijective function must be both injective and surjective, which means it is reversible.

Injective indicates that each element in the domain corresponds uniquely to an element in the codomain.

Surjective denotes that every element in the codomain relates to exactly one element in the domain.

This ensures there are no unmatched elements.

If we consider set A as the function's domain and set B as the codomain.

The core question then becomes: can the set {17, 34, 51, 68, 85,...} be in bijection with the set {11, 22, 33, 44, 55,...}?

Notice that the two sets share no common elements, as 17 and 34 are coprime.

A bijective function can only be established between sets A and B or B and A if both sets possess the same cardinality (number of elements).

Indeed, the cardinality of sets A and B is identical: both sets are of equal size, affirming that a bijective relationship exists between them.

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Which is a y-intercept of the continuous function in the table? (0, –6) (–2, 0) (–6, 0) (0, –2)
Zina [3914]

The y-intercept is the location where any graph meets the y-axis.

Conversely, the x-intercept is where a graph intersects the x-axis.

This indicates that the coordinates at the intercept will always have the x-value as 0. Therefore, points of the format (0, y) represent y-intercepts, while points in the format (x, 0) indicate x-intercepts.

The provided points are:

(0,-6): y-intercept

(-2,0): x-intercept

(-6,0): x-intercept

(0,-2): y-intercept

3 0
7 days ago
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Which is the solution of the quadratic equation (4y – 3)2 = 72? y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction a
Inessa [3907]

Answer:

y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction

Explicación paso a paso:

La ecuación cuadrática que tenemos es (4y - 3)² = 72

Debemos encontrar el valor de y.

Ahora, 4y - 3 = ± 6√2

⇒ 4y = 3 ± 6√2

⇒ y = \frac{3 + 6\sqrt{2} }{4} y y = \frac{3 - 6\sqrt{2} }{4}

Por lo tanto, las soluciones son y = StartFraction 3 + 6 StartRoot 2 EndRoot Over 4 EndFraction y y = StartFraction 3 menos 6 StartRoot 2 EndRoot Over 4 EndFraction (Respuesta)

6 0
11 days ago
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A survey of 100 people found that 35 people exercise in the morning, 45 people exercise in the afternoon, and 20 people exercise
Zina [3914]
Out of 100 surveyed individuals, 35 work out in the morning, 45 in the afternoon, and 20 at night.

Jim is accurate.....
The ratio of morning exercisers to the whole group is 35/100.
The ratio of afternoon exercisers is 45/100.
The ratio for night exercisers is 20/100.
7 0
4 days ago
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Carmen has $30 in store bucks and a 25% discount coupon for a local department store. What maximum dollar amount can Carmen purc
lawyer [4008]

Answer:

$110.

Step-by-step explanation:

Let x represent the cost of the item that Carmen bought from the department store.

Carmen possesses $30 in store bucks along with a 25% discount coupon for a local department store. Our goal is to determine the maximum cost for Carmen's purchase such that after applying her store bucks and discount, her total remains at or below $60 before sales tax.

Since the $30 in store bucks is deducted prior to applying the 25% discount, we need to find x such that x - 30 minus 25% of (x - 30) must be less than or equal to 60. This can be set up as an equation:

x-30-((x-30)\times\frac{25}{100})\leq 60

x-30-((x-30)\times 0.25)\leq 60

x-30-(0.25x-7.5)\leq 60

x-30-0.25x+7.5\leq 60

0.75x-22.5\leq 60

0.75x-22.5+22.5\leq 60+22.5

0.75x\leq 82.5

\frac{0.75x}{0.75}\leq \frac{82.5}{0.75}

x\leq 110

Thus, Carmen's purchases should total no more than $110 before sales tax.

3 0
5 days ago
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To celebrate their 30th birthdays, brothers Mario and Luigi of the Nintendo Mario video game franchise wish to study the distrib
Zina [3914]

Answer:

Step-by-step explanation:

<pGreetings!

a. The variable X represents the height of a Goomba, which follows a normal distribution with a mean of μ= 12 inches and a standard deviation of δ= 6 inches.

To find the probability that a Goomba picked at random has a height between 13 and 15 inches, you express it as:

P(13≤X≤15)

Considering that standard normal probability tables provide cumulative values, you can express this range as the cumulative probability up to 15 minus the cumulative probability up to 13. You'll first need to standardize these variable heights to obtain corresponding Z values:

P(X≤15) - P(X≤13)

P(Z≤(15-12)/6) - P(Z≤(13-12)/6)

P(Z≤0.33) - P(Z≤0.17)= 0.62930 - 0.56749= 0.06181

b. Now we have Y as the variable indicating the height of a Koopa Troopa. This variable also follows a normal distribution, with a mean μ= 15 inches and a standard deviation δ=3 inches.

The query concerns the probability that a Koopa Troopa stands taller than 75% of Goombas.

First step:

You need to determine the height of a randomly chosen Koopa Troopa that exceeds 75% of the Goomba population.

This entails determining the value of X corresponding to the limit below which 75% of the population falls, denoted by:

P(X ≤ b)= 0.75

Step 2:

Search the standard normal distribution for the Z value that has 0.75 beneath it:

Z_{0.75}= 0.674

Next, you will reverse the standardization to solve for "b"

Z= (b - μ)/δ

b= (Z*δ)+μ

b= (0.674*6)+12

b= 16.044 inches

Step 3:

With the height that identifies a Koopa Troopa taller than 75% of the Goomba population determined, compute the probability of selecting that Koopa Troopa:

P(Y≤16.044)

This time, utilize the Koopa’s average height and standard deviation to find the probability:

P(Z≤(16.044-15)/3)

P(Z≤0.348)= 0.636

The likelihood of randomly selecting a Koopa Troopa that is taller than 75% of Goombas is 63.6%

I hope this information is useful!

3 0
4 days ago
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