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qaws
1 day ago
12

In the diagram, point O is the center of the circle and AC¯¯¯¯¯ and BD¯¯¯¯¯ intersect at point E. If m∠AOB = 90° and

Mathematics
2 answers:
lawyer [9.2K]1 day ago
6 0

Answer:

53

Step-by-step explanation:

When I entered 53 into PLATO, it appears to be the correct answer.

Zina [9.1K]1 day ago
5 0

Answer: 53^{\circ}

Step-by-step explanation:

Given:  Point O denotes the circle's center, AC and BD are chords of the circle, while E is where AC intersects BD,

m∠AOB = 90° and m∠COD = 16°

We need to find: m∠CED

By connecting points B and C (construction)

m∠AOB = 90° ⇒ m∠ACB = 45° (based on the center angle theorem)

Similarly, joining points A and D leads to

m∠AOB = 90° ⇒ m∠ADB = 45°

Since triangles COD and CBD share the same arc CD within the circle about center O.

Therefore, m∠CBD = m∠COD/2 = 16/2 = 8°

Thus, m∠CBD =  8°

However, m∠CED = m∠CBD + m∠ACB  (using the exterior angle property of the triangle)

Thus,  m∠CED = 8° + 45° = 53°

Hence,  m∠CED  = 53°

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