Write an application that throws and catches an ArithmeticException when you attempt to take the square root of a negative value

Question

2 months ago

15

Write an application that throws and catches an ArithmeticException when you attempt to take the square root of a negative value

. Prompt the user for an input value and try the Math.sqrt() method on it. The application either displays the square root or catches the thrown Exception and displays the message Can't take square root of negative number

Computers and Technology

1 answer:

Harlamova29_29 [1K] · Answer 1 · 2026-02-26T23:42:00+03:00

The code relevant to the problem in question:

import java.util.Scanner;

public class Test {

public static void main(String[] args) {

double number;

double squareRootOfNumber;

String userInput = null;

Scanner scanner = new Scanner(System.in);

System.out.println("Please enter a number: ");

userInput = scanner.next();

number = Double.parseDouble(userInput);

squareRootOfNumber = Math.sqrt(number);

if (number < 0) {

throw new ArithmeticException("Cannot compute the square root of a negative number");

}

System.out.format("The square root of the entered number is %.2f %n", squareRootOfNumber);

}

The program will output:

Please enter a number:

-90

Exception in thread "main" java.lang.ArithmeticException: Cannot compute the square root of a negative number at com..ans.Test.main(Test.java:18)

Explanation:

The standard Java library function java.lang.Math.sqrt does not throw an ArithmeticException for negative arguments, hence there’s no need to enclose your code in a try/catch block.

Instead, we manually trigger ArithmeticException using the throw keyword:

throw new ArithmeticException("Cannot compute the square root of a negative number");