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Genrish500
2 months ago
5

A computer program is tested by 5 independent tests. If there is an error, these tests will discover it with probabilities 0.1,

0.2, 0.3, 0.4, and 0.5, respectively. Suppose that the program contains an error. What is the probability that it will be found
Computers and Technology
1 answer:
ivann1987 [1K]2 months ago
5 0

Answer:

0.8488

Explanation:

Let E denote the error from test 1.

Let F represent the error from test 2.

Let G signify the error from test 3.

Let H indicate the error from test 4.

Let I be the error from test 5.

Given values are P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5

As a result, P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5

Assuming test independence, P(not E & not F & not G & not H & not I) can be expressed as P(notE)*P(notF)*P(notG)*P(notH)*P(notI) =0.9*0.8*0.7*0.6*0.5 =0.1512

P(at least one test finding an error) is equal to 1 minus the probability of not finding any errors: 1 - P(not E & not F & not G & not H & not I) = 1-0.1512 = 0.8488

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