Answer:
0.8488
Explanation:
Let E denote the error from test 1.
Let F represent the error from test 2.
Let G signify the error from test 3.
Let H indicate the error from test 4.
Let I be the error from test 5.
Given values are P(E)=0.1, P(F)=0.2, P(G)=0.3, P (H)= 0.4, P (I)=0.5
As a result, P(notE)=0.9, P(notF)=0.8, P(notG)=0.7, P(not H)=0.6, P (notI)=0.5
Assuming test independence, P(not E & not F & not G & not H & not I) can be expressed as P(notE)*P(notF)*P(notG)*P(notH)*P(notI) =0.9*0.8*0.7*0.6*0.5 =0.1512
P(at least one test finding an error) is equal to 1 minus the probability of not finding any errors: 1 - P(not E & not F & not G & not H & not I) = 1-0.1512 = 0.8488