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olasank
6 days ago
9

The heights of 200 adults were recorded and divided into two categories.

Mathematics
2 answers:
AnnZ [3.8K]6 days ago
8 0
The response is A

I hope this information is useful.
Svet_ta [4.2K]6 days ago
3 0

Answer: the correct option is B

Step-by-step explanation:

By adding 14 and 6, you get 16. Then, adding 88 to 16 results in 104. Subtracting this from 200 gives 96.

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The hourly wage increases each employee receives each year depends on the number of years of service. Every three years of servi
Inessa [3895]

Answer:

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

Step-by-step explanation:

Based on the details provided:

Employees with less than 3 years receive an increase of $0.50 hourly

Employees with at least 3 years but under 6 years receive $1.00 increase hourly

Employees with a minimum of 6 years and less than 9 get $1.50 increase hourly

Employees with at least 9 years but below 12 years receive $2.00 increase hourly

This information can be expressed as a piecewise function:

________{0.50 if x < 3

________{1.00 if 3 ≤ x < 6

f(x) = ____{1.50 if 6 ≤ x < 9

________{2.00 if 9 ≤ x < 12

The conditions are outlined in the piecewise function above with x indicating the number of years employed.

6 0
5 days ago
3.7.6 .WP A state runs a lottery in which six numbers are randomly selected from 40 without replacement. A player chooses six nu
PIT_PIT [3895]

Answer:

a) 2.60x10^-7

b) 5.31x10^-5

c) 2.19x10^-3

Step-by-step explanation:

X=the number of hits

Probability can be determined by taking the number of successful outcomes and dividing it by the total number of possible outcomes.

Now

a) P(X=6)=P({1, 1, 1, 1, 1, 1})=6/40*5/39*4/38*3/37*2/36*1/35=2.60x10^-7

b) P(X=5)=P({0, 1, 1, 1, 1, 1})+P({1, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 1, 0}), and each scenario carries the same probability

P(X=5)=6P({1, 1, 1, 1, 1, 0})=6*(6/40*5/39*4/38*3/37*2/36*34/35)=5.31x10^-5

c) P(X=4)=P({0, 0, 1, 1, 1, 1})+...+P({1, 1, 1, 1, 0, 0}), where each case has an identical probability.

P(X=4)=(^6_4)P({1, 1, 1, 1, 0, 0})=\frac{6!}{4!(6-4)!}(\frac{6}{40} \frac{5}{39} \frac{4}{38} \frac{3}{37} \frac{34}{36} \frac{33}{35} )=2.19\times 10^{-3}

3 0
8 days ago
What is the following quotient? StartFraction StartRoot 6 EndRoot + StartRoot 11 EndRoot Over StartRoot 5 EndRoot + StartRoot 3
babunello [3607]

Answer:

StartFraction StartRoot 30 EndRoot minus 3 StartRoot 2 EndRoot + StartRoot 55 EndRoot minus StartRoot 33 EndRoot Over 2

Step-by-step explanation:

We are given the surdic equation depicted in \frac{\sqrt{6}+\sqrt{11} }{\sqrt{5}+\sqrt{3} }\\.

To calculate the quotient, we will rationalize by multiplying both the numerator and denominator of the function by the conjugate of the denominator.

The denominator shown in \sqrt{5}+\sqrt{3} has a conjugate of \sqrt{5}-\sqrt{3}.

After multiplying by \sqrt{5}-\sqrt{3}, we achieve;

= \frac{\sqrt{6}+\sqrt{11} }{\sqrt{5}+\sqrt{3} } * \frac{\sqrt{5}-\sqrt{3} }{\sqrt{5}-\sqrt{3} }\\

= \frac{\sqrt{30}- \sqrt{18}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- \sqrt{9*2}+\sqrt{55}-\sqrt{33}}{2}\\= \frac{\sqrt{30}- 3\sqrt{2}+\sqrt{55}-\sqrt{33}}{2}

The resulting expression provides the needed answer.

5 0
9 days ago
Read 2 more answers
The table gives estimates of the world population, in millions, from 1750 to 2000. (Round your answers to the nearest million.)
zzz [4002]

Answer:

A.) 1508; 1870

B.) 2083

C.) 3972

Step-by-step explanation:

The general equation for an exponential model is:

A = A0e^rt

A0 represents the initial population

A indicates the final population

r is the growth rate; t denotes time

1)

Considering the years 1750 and 1800

Time interval, t = 1800 - 1750 = 50 years

Starting population = 790

End population = 980

To find the growth rate:

980 = 790e^50r

980/790 = e^50r

Applying the natural logarithm to both sides

In(980/790) = 50r

0.2155196 = 50r

r = 0.2155196/50

r = 0.0043103

Using this growth rate, let's forecast the population for 1900

t = 1900 - 1750 = 150 years

A = 790e^150*0.0043103

A = 790e^0.6465588

A = 1508.0788; approximately 1508 million people

In 1950:

t = 1950 - 1750 = 200

A = 790e^200*0.0043103

A = 790e^0.86206

A = 1870.7467; around 1870 million people

2.)

Exponential model from 1800 to 1850

Initial population in 1800 = 980

Final population in 1850 = 1260

t = 1850 - 1800 = 50

Utilizing the exponential equation, we find the growth rate:

1260 = 980e^50r

1260/980 = e^50r

Taking the natural logarithm of both sides

In(1260/980) = 50r

0.2513144 = 50r

r = 0.2513144/50

r = 0.0050262

Utilizing this model, the anticipated population in 1950:

In 1950:

t = 1950 - 1800 = 150

A = 980e^150*0.0050262

A = 980e^0.7539432

A = 2082.8571; approximately 2083 million people

3.)

For 1900: 1650,

For 1950: 2560

t = 1900 - 1950 = 50

Utilizing the exponential formula, we derive the growth rate:

2560 = 1650e^50r

2560/1650 = e^50r

Logarithm both sides

In(2560/1650) = 50r

0.4392319 = 50r

r = 0.4392319/50

r = 0.0087846

Using this model, the projected population for 2000:

In 2000:

t = 2000 - 1900 = 100

A = 1650e^100*0.0087846

A = 1650e^0.8784639

A = 3971.8787; approximately 3972 million people

3 0
2 days ago
Consider the equation pV=kTN , where k is a constant. Select all of the correct answers that describe the variation between vari
PIT_PIT [3895]

Answer:

Refer to the following:

Step-by-step explanation:

Rule: If variables appear on the same side of the equation, they have INVERSE variation.

If the variables are located on opposite sides of the equation, they have DIRECT variation.

a) T and V

  • Opposite sides
  • Directly related

b) p and T

  • Opposite sides
  • Directly related

c) N and V

  • Opposite sides
  • Directly related

d)  N and T

  • Same side
  • Inversely related

e)  p and N

  • Opposite sides
  • Directly related

f)  V and P

  • Same side
  • Inversely related.
4 0
15 hours ago
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