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nordsb
6 days ago
11

One afternoon the water park sold 525 tickets for a total of $13,545 . Child tickets cost $19 each, and adult tickets cost $40 e

ach. How many of each kind of ticket were sold?
Mathematics
2 answers:
Inessa [9K]6 days ago
8 0
You will need to establish two equations for this scenario. Let's begin with the ticket sales & relevant variables.

c = number of child tickets sold
a = number of adult tickets sold

c + a = 525

Next, let's create the equation for the revenues.

c = number of child tickets sold
a = number of adult tickets sold

19c + 40a = 13,545

Now align the two equations together.

c + a = 525
19c + 40a = 13,545

Next, I'll isolate one of the variables.

c + a = 525
-a -a

c = 525 - a

Plugging into the other equation gives

19(525) + 40a = 13,545
Let's solve for it.
9,975 + 40a = 13,545
-9,975
40a = 3,570 / 40
a = 89.25
Now round 89?

Then substitute a back into the second equation

c + 89 = 525
-89 -89
c = 436

So the conclusion is:
Sold 89 adult tickets.
Sold 436 child tickets.
PIT_PIT [9.1K]6 days ago
5 0

Result: The number of child tickets is 355 and the adult tickets total 170 respectively


Detailed explanation:

Let the child ticket count be x

and the adult ticket count as y

We have x+y=525.........[1]

19x+40y=13545.........[2]

By multiplying  [1] by 19

19x+19y=9975........[3]

Subtracting [3] from [2]

19x+40y-19x -19y= 13545-9975

21y=3570

By dividing both sides by 21

y=170

Inserting the value of y into [1]

x+170=525

Subtracting 170 from both sides

x+170-170= 525-170

x=355

Number of child tickets = 355

Number of adult tickets = 170

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