Answer:
m∠EBC=34°
Step-by-step explanation:
We establish that
m∠DBC=m∠DBE+m∠EBC
Refer to the accompanying diagram for clarity on the issue
Replace the known values in the equation and determine x
Calculate the size of angle EBC
m∠EBC=(3x+13)°
Insert the value for x
m∠EBC=(3(7)+13)°
m∠EBC=(21+13)°
m∠EBC=34°
Answer:
F(t) = 10 + 5(t)
Step-by-step explanation:
The complete question is as follows;
Anumeha is mowing lawns for a summer job. For each lawn she mows, she charges a $10 starting fee plus an hourly rate. For example, her fee for a 5-hour job is $35. Let f(t) denote Anumeha's fee for a job f (in dollars) based on how many hours (t) were needed to finish it. Write the formula for this function.
Solution
We aim to establish the formula F(t) representing the fee Anumeha charges per job.
Key to formulating this function is understanding the constant charge she applies per job.
We know she earns $35 for mowing for 5 hours.
Therefore, the constant fee can be deduced as follows;
Since it’s a $10 starting fee along with an hourly rate;
35 = 10 + 5(x)
where x refers to the hourly rate
35 = 10 + 5x
5x = 35-10
5x = 25
x = 25/5
x = $5
This indicates that she charges a constant fee of $5 per hour
Thus, we can now write the equation.
F(t) = 10 + 5(t)
where t represents the number of hours spent on each job
This is the solution:
(3m^-2 n)^-3 / 6mn^-2
For the first step: apply the power distribution3^-3 m^-2*-3 n^-3 / 6mn^-2
In the second step: utilize the product and quotient rulesm^6 n^2/ 3^3 *6*m*n^3
Lastly, simplify the expressionm^5/162n
The conclusive answer is m^5/162n
Hope this aids you.:)
To identify the corresponding equation, you can follow these steps:
ax^2 + bx + c = 0
where a = -2
b = 1
c = 3
-2x^2 + x + 3 = 0
The right result will show as a: 0 = <span>-2x^2 + x + 3.</span>
The attached graph illustrates the region. The centroid's coordinates are (5/3, 1). The centroid's coordinates are determined by averaging the coordinates of the area; Oₓ = (Aₓ+Bₓ+Cₓ)/3 = (0+1+4)/3 = 5/3 and O(y) = (A(y) + B(y) + C(y)) = (0+3+0)/3=3/3=1.
