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Mariana
1 month ago
13

A hollow sphere sits snugly in a foam cube so that the sphere touches each side of the cube. Find the volume of the foam.

Mathematics
1 answer:
Leona [12.6K]1 month ago
5 0

Answer:

                          π

V-foam = 4r³( 2 - ----- )

                             3

Step-by-step explanation:

Let r denote the radius of the sphere. The volume of the sphere is expressed as

V = (4/3)(π)(r³).

Next, understand that the cube's side length is 2r, hence the cube's volume is

V = (2r)³, which equals 8r³.

The volume of the foam is derived from the cube's volume subtracting that of the sphere:

V-foam = 8r³ - (4/3)(π)(r³). This can be simplified to

                          π

V-foam = 4r³( 2 - ----- )

                             3

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The blood platelet counts of a group of women have a​ bell-shaped distribution with a mean of 247.9 and a standard deviation of
PIT_PIT [12445]

Answer:

A) The estimated proportion of women whose platelet counts fall within 2 standard deviations of the mean, or between 118.5 and 377.3, is 95%.

B) The estimated percentage of women with platelet counts ranging from 53.8 to 442.0 is 99.7%.

Step-by-step explanation:

Provided data:

mean;μ = 247.9

standard deviation;σ = 64.7

A) We seek to find the estimated percentage of women with platelet counts within 2 standard deviations from the mean, which translates to values between 118.5 and 377.3.

Based on the attached image, the empirical curve indicates that the likelihood within 1 standard deviation of the mean is (34% + 34%) = 68%.

In contrast, the likelihood within 2 standard deviations from the mean is (13.5% + 34% + 34% + 13.5%) = 95%

Therefore, the estimated percentage of women having platelet counts within 2 standard deviations of the mean, or ranging from 118.5 to 377.3, equals 95%

B) Next, we want to determine the estimated percentage of women with platelet counts between 53.8 and 442.0.

The values of 53.8 and 442.0 correspond to 3 standard deviations from the mean.

Let’s verify that.

Since mean;μ = 247.9

standard deviation;σ = 64.7;

μ = 247.9

σ = 64.7

μ + 3σ = 247.9 + 3(64.7) = 442

Also;

μ - 3σ = 247.9 - 3(64.7) = 53.8

From the attached empirical curve, it can be seen that at 3 standard deviations from the mean, the probability percentage is;

(2.35% + 13.5% + 34% + 34% + 13.5% + 2.35%) = 99.7%

5 0
16 days ago
Ella spent her whole allowance of $2.00, plus the 16¢ she had left over from last week, in bubble gum. If the pieces of gum had
Zina [12379]
Determining the answer here is quite straightforward. Ella has a total of $2.16, and we need to ascertain the cost per piece of gum.
It is known that if the gum cost one cent less, she would have acquired three more pieces.
 Currently, with 8 pieces priced at 27 cents each, a reduced price would allow her to have 8.64 pieces. This outcome, even after rounding, is incorrect as it does not yield 11.
 For 9 pieces at 24 cents each, a cheaper price would mean she could have 9.39 pieces, which still does not round to 12, indicating it's incorrect.
 At 16 pieces costing 13.5 cents each, at one cent less, she would acquire 17.28 pieces, which also confirms it's wrong because rounding does not yield 19.
 When purchasing 24 pieces at 9 cents each, with the cheaper price, she could buy 27 pieces, which is valid since 27-24 equals 3.
 Therefore, the correct answer is D) 24
3 0
23 days ago
Read 2 more answers
LMN is a straight angle. Find m LMP and m NMP​
PIT_PIT [12445]

Answer:

(-16x + 13)° + (-20x + 23)° = 180° (ángulo recto)

-16x° + 13° - 20x° + 23° = 180°

-36x° + 36° = 180°

-36x° = 180° - 36°

-36x° = 144°

-x° = 144°/(-36)

x° = 36°

Espero que puedas conocer esta respuesta

3 0
1 month ago
A survey conducted five years ago by the health center at a university showed that 18% of the students smoked at the time. This
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The test statistic (Z) is 2.5767, and the p-value of the test is 0.009975. The null hypothesis suggests that the smoking rate among students has not changed, while the alternative indicates otherwise. The z-statistic for the sampled proportion is computed, yielding z ≈ 2.5767. As we investigate whether the smoking percentage has shifted over the preceding five years, the two-tailed p-value is found to be 0.009975. This result is significant at a 99% confidence level, demonstrating substantial evidence that the percentage of smoking students has changed.
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1 month ago
What is the 1000th root of the expression 5(^10^10)
lawyer [12517]

Solution:

feet

Detailed explanation:

3 0
29 days ago
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