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ivanzaharov
6 days ago
10

A department store purchases logo shirts at a cost of $10 per shirt. They increase the price 100% and put them on the sales floo

r. Every month that a shirt doesn’t sell, the store reduces the selling price by 25%. After three monthly reductions, the final shirt from the shipment is sold. There is a 5% sales tax on the selling price. Explain the steps for finding the final cost to the customer for that shirt?
Mathematics
2 answers:
Inessa [3.9K]6 days ago
7 0

The initial selling price is determined by multiplying 100% with $10, then adding that to the original $10. The logo shirt is priced at $20 on the sales floor. In the following three months, the sale price is recalculated by taking 75% of the current sale price. To calculate the tax, multiply the final sale price by 5% and add it to the discounted price.

lawyer [4K]6 days ago
5 0

Answer:

Sample response: The initial selling price is calculated by multiplying 100% with $10 and adding it to the original $10. The logo shirt is available for $20. Over the next three months, the selling price decreases by 25% each month, found by multiplying the current sale price by 75%. The 5% sales tax is then calculated on the final discounted price and added to that price.

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babunello [3635]

Answer:

\frac{dV(t)}{dt} = - 1675.38

Step-by-step explanation:

In 2017, the kitchen equipment's value was recorded at $14,550.

V(0)=$14550

Its following value is represented by V(t)=14550e^{-0.158t.

We need to ascertain the rate of value change as of January 1, 2019.

V(t)=14550e^{-0.158t

\frac{dV(t)}{dt} =\frac{d}{dt}14550e^{-0.158t

\frac{dV(t)}{dt} =14550 \frac{d}{dt}e^{-0.158t

\\Let u= -0.158t,\frac{du}{dt}=-0.158

\frac{dV(t)}{dt} =14550 \frac{d}{du}e^u\frac{du}{dt}

\frac{dV(t)}{dt} =14550 X -0.158 e^{-0.158t}=-2298.9e^{-0.158t}

As of 2019, which is 2 years later, we set t=2.

The rate of value change is

\frac{dV(t)}{dt} =-2298.9e^{-0.158X2}

=\frac{dV(t)}{dt} =-2298.9e^{-0.316}= -1675.38

3 0
3 days ago
Alice and Briana each participate in a 5 kilometer race. Alice's distance covered, in kilometers, after t minutes can be modeled
PIT_PIT [3919]

Answer:

a. Alice

b. Briana

c. 0.51 minutes

Step-by-step explanation:

a. Alice's formula is applicable for any t > 0 minutes, while Briana’s is only applicable when

2t - 1 > 0

2t > 1

t > 1/2 minutes

b. They complete the race when their total distance equals 5 kilometers. For Alice:

t/4 = 5

t = 20 minutes

For Briana:

√(2t - 1) = 5

2t - 1 = 25

2t = 26

t = 13 minutes

c. They reach the same point when they have traveled the same distance, expressed as:

t/4 = √(2t - 1)

(t/4)² = 2t - 1

t²/16 = 2t - 1

t² = 16(2t - 1)

t² = 32t - 16

t² - 32t + 16 = 0

Using the quadratic formula:

t = \frac{-b \pm \sqrt{b^2 - 4(a)(c)}}{2(a)}

t = \frac{32 \pm \sqrt{-32^2 - 4(1)(16)}}{2(1)}

t = \frac{32 \pm 30.98}{2}

t_1 = \frac{32 + 30.98}{2}

t_1 = 31.49

t_2 = \frac{32 - 30.98}{2}

t_2 = 0.51

Only the second solution fits this scenario because the race concluded before they took 31.49 minutes.

4 0
4 days ago
Read 2 more answers
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Inessa [3907]
H(t) = -16t² + 704t = -16(t² - 44t)
Transforming to vertex form: -16(t² - 44t + 484) + 704
h(t) = -16(t - 22)² + 704
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Inessa [3907]

Step-by-step explanation:

Let 'P' represent the principal amount

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P = $1000

R = 3%

T = 4 years

We can compute the simple interest using,

Interest = (P x R x T) / 100

= (1000 x 3 x 4) / 100

= 12000 / 100

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Thus, the simple interest over 4 years totals $120.

Total amount = P + Interest

= 1000 + 120

= $1120

Consequently, the account will have $1120 after 4 years.

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Response:

d

Detailed explanation:

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