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AleksAgata
2 months ago
14

Using cell references, enter a formula in cell B6 to calculate monthly payments for the loan described in this worksheet. The an

nual interest rate is stored in cell B3, the number of payments in cell B4, and the loan amount in cell B2. Omit the optional arguments. The result of the formula should be a negative number.
Mathematics
1 answer:
Zina [12.3K]2 months ago
5 0

Response:

Here is the solution to the question:

Detailed Steps:

The following steps will be followed in this task:

  • Step 1: Utilize the formulas tab on the sheet where you will apply the function found in the FLG "Function Library group".
  • Step 2: Click on the Financial button, then select PMT.
  • Step 3: After selecting PMT, input "B3/12" into the rate argument box.
  • Step 4: In B4, fill in the Nper argument box with the value found in cell "B2" for the Pv argument box.
  • Step 5: Click the OK button to finish.
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Victor had 15-kilometers start on Chase. How long will it take Chase to catch Victor if Victor travels at 65 kilometers per hour
tester [12383]

Answer:

  1/2 hour

Step-by-step explanation:

The distance of the head start decreases at a rate of (95-65) = 30 km/h. Thus, Chase will reach Victor after...

  time = distance/speed = (15 km)/(30 km/h) = 1/2 hour

Chase will take 1/2 hour to catch up with Victor.

4 0
29 days ago
A beverage manufacturer performs a taste-test and discovers that people like their fizzy beverages best when the radius of the b
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Since the radius is provided, we can formulate the equation and compute the volume V.

0.3= \sqrt[3]{ \frac{3V}{4 \pi } }

Next, we will cube both sides to eliminate the cube root resulting in:

0.027= \frac{3V}{4 \pi }

Then, to remove the fraction, we multiply both sides by 4 pi:

0.339=3V

Finally, we can divide both sides by 3 to derive V

V=0.11

Thus, the volume amounts to 0.11 cubic mm.


5 0
1 month ago
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Megan and Suzanne each have a plant. They track the growth of their plants for four weeks. Whose plant grew at a faster rate, an
AnnZ [12381]
In the context of science, the rate is defined as a <span>metric that is evaluated in relation to another measured metric. To determine the rate for each set of data, we calculate the slope. The calculations proceed as follows:

Megan's growth rate = (12 - 4.5) / (4 - 1) = 2.5 inches weekly
Suzanne's growth rate = (11 - 5) / (4 - 1) = 0.5 inches weekly

Thus, it's clear that Megan’s plant grew more rapidly at a rate of </span><span>2.5 inches each week.</span>
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1 month ago
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Jane is training for a triathlon. After swimming a few laps, she leaves the health club and bikes 16 miles south. She then runs
PIT_PIT [12445]

Answer:

The formula to determine the distance Jane's trainer bikes is x=\sqrt{16^2+12^2}.

Detailed explanation:

A diagram has been included for clarity.

Known values:

Distance biked to the south = 16 miles

Distance ran west = 12 miles

We need to determine the distance covered by Jane's trainer.

Solution:

Let the biking distance be represented by 'x'.

We will assume it forms a right-angled triangle.

According to the Pythagorean theorem, it states that;

"The square of the hypotenuse is equal to the sum of the squares of the other two sides."

When set in equation form, this gives us;

x^2=16^2+12^2\\\\x=\sqrt{16^2+12^2}

Thus, the equation representing the distance biked by Jane's trainer is x=\sqrt{16^2+12^2}.

Upon solving, we find;

x=\sqrt{16^2+12^2}\\\\x= \sqrt{256+144}\\ \\x=\sqrt{400} \\\\x=20\ miles

Consequently, Jane's trainer covers a distance of 20 miles.

7 0
12 days ago
A father lifts a toddler 1.5 m up in the air. The child gains 187.5 J of energy in her gravitational potential energy store as a
Svet_ta [12734]

The toddler weighs 12.5 kg.

In-depth explanation:

The formula for gravitational potential energy is Ep=mgh where;

Ep=gravitational potential energy

m=mass of an object

g=gravitational field strength

h=height in meters

Given that; h= 1.5m, Ep=187.5J, g=10 N/kg then finding m;

Ep=mgh

187.5=m*10*1.5

187.5=15m

187.5/15 =15m/15

m=12.5 kg

Learn More

  • Gravitation potential energy:

Keywords: Mass, gravitational potential energy

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29 days ago
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