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2 months ago

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A periscope is 5 feet above the surface of the ocean. Through it can be seen a ship that rises to 50 feet above the water. To th

e nearest mile, the farthest away that the ship could be is a0 miles.

1 answer:

PIT_PIT [12.4K]2 months ago

5 0

The maximum distance visible on Earth is calculated using the formula $d=\sqrt{8,000h_1} + \sqrt{8,000h_2}$

$h_1$ = your initial height and $h_2$ = your secondary height

In this case, $h_1=5$ represents the height of the periscope and $h_2=50$ denotes the height of the ship, leading us to a distance of 832.45553203368 feet. However, rounding to the nearest mile yields the answer as $11^a^0$

If there are any discrepancies, please inform me and I will recalculate!

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Chad lives in California and makes $59,500 a year. If the median annual income is $61,021 in California and $50,233 in the Unite

zzz [12365]

<span>It is likely that Chad will qualify, as his annual earnings are below California's median yearly income.

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1 month ago

Read 2 more answers

The computers of six faculty members in a certain department are to be replaced. Two of the faculty members have selected laptop

lawyer [12517]

Answer:

a. $\frac{1}{15}$

b. $\frac{2}{5}$

c. $\frac{14}{15}$

d. $\frac{8}{15}$

Step-by-step explanation:

There are four desktop computers and two laptops.

On a specific day, we will set up 2 of these computers.

To find:

a. What is the probability that both selected computers are laptops?

b. What is the probability that both computers are desktops?

c. What is the probability that at least one computer is a desktop?

d. What is the probability that at least one of each type of computer is included?

Solution:

Using the probability formula for event E:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

a. The number of successful outcomes for both computers being laptops = $_2C_2$ = 1

Total possible outcomes = 15

The needed probability is $\frac{1}{15}$ .

b. The successful outcomes for both being desktop computers = $_4C_2=6$

Total possible outcomes = 15

The required probability is $\frac{6}{15} = \frac{2}{5}$ .

c. For at least one desktop:

Two scenarios exist:

1. 1 desktop and 1 laptop:

Successful outcomes = $_2C_1\times _4C_1 = 8$

2. Both are desktops:

Successful outcomes = $_4C_2=6$

Total successful outcomes = 8 + 6 = 14

The needed probability is $\frac{14}{15}$ .

d. 1 desktop and 1 laptop:

Successful outcomes = $_2C_1\times _4C_1 = 8$

Total outcomes = 15

The required probability is $\frac{8}{15}$ .

8 0

2 months ago

The ground-state wave function for a particle confined to a one-dimensional box of length L is Ψ=(2/L)^1/2 Sin(πx/L). Suppose th

AnnZ [12381]

Respuesta:

(a) 4.98x10⁻⁵

(b) 7.89x10⁻⁶

(c) 1.89x10⁻⁴

(d) 0.5

(e) 2.9x10⁻²

Explicación paso a paso:

La probabilidad (P) de encontrar la partícula está dada por:

$P=\int_{x_{1}}^{x_{2}}(\Psi\cdot \Psi) dx = \int_{x_{1}}^{x_{2}} ((2/L)^{1/2} Sin(\pi x/L))^{2}dx$

$P = \int_{x_{1}}^{x_{2}} (2/L) Sin^{2}(\pi x/L)dx$ (1)

La solución de la integral de la ecuación (1) es:

$P=\frac{2}{L} [\frac{X}{2} - \frac{Sin(2\pi x/L)}{4\pi /L}]|_{x_{1}}^{x_{2}}$

(a) La probabilidad de encontrar la partícula entre x = 4.95 nm y 5.05 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{4.95}^{5.05} = 4.98 \cdot 10^{-5}$

(b) La probabilidad de encontrar la partícula entre x = 1.95 nm y 2.05 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{1.95}^{2.05} = 7.89 \cdot 10^{-6}$

(c) La probabilidad de encontrar la partícula entre x = 9.90 nm y 10.00 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{9.90}^{10.00} = 1.89 \cdot 10^{-4}$

(d) La probabilidad de encontrar la partícula en la mitad derecha de la caja, es decir, entre x = 0 nm y 50 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{50.00} = 0.5$

(e) La probabilidad de encontrar la partícula en el tercio central de la caja, es decir, entre x = 0 nm y 100/6 nm es:

$P=\frac{2}{100} [\frac{X}{2} - \frac{Sin(2\pi x/100)}{4\pi /100}]|_{0}^{16.7} = 2.9 \cdot 10^{-2}$

Espero que te ayude.

3 0

2 months ago