Ask question

Ask question

All categories

1 month ago

10

The University of Central Florida's cheerleading team has eighteen males and twenty-one females. If h represents the height of a

team member, the inequality 260 ≤ 4h + 28 < 324 , represents the range of heights of the cheerleaders, in inches. Select all possible heights for the University of Central Florida's cheerleaders.

1 answer:

Leona [12.6K]1 month ago

3 0

Answer:

The range of cheerleaders' heights lies within the interval [58, 74)

It includes all real numbers from 58 inches and above, but below 74 inches.

Step-by-step explanation:

we have

$260 \leq 4h+28$

Separate the combined inequality into two distinct inequalities

$260 \leq 4h+28$ -----> inequality A

$4h+28$ -----> inequality B

Solve inequality A

$260 \leq 4h+28$

Subtract 28 from both sides

$232 \leq 4h$

Split by 4 on both sides

$58 \leq h$

Reformulate

$h \geq 58\ in$

Address inequality B

$4h+28$

Subtract 28 from both sides

$4h$

Split by 4 on both sides

$h$

consequently

The height range of the cheerleaders is the interval [58, 74)

It consists of every real number starting from 58 inches and less than 74 inches

You might be interested in

The table compares x, the number of minutes of television Sam watched each day, to y, the number of minutes she spent exercising

Inessa [12570]

The predicted outcome is 83 minutes. I hope this is useful to you.

6 0

1 month ago

Read 2 more answers

What is the solution to the system of equations? y = A system of equations. Y equals StartFraction one-third EndFraction minus 1

lawyer [12517]

Response:

$(6,-8)$ .

Detailed explanation:

We have a set of equations provided. Our task is to find the solution for this system.

$y=\frac{1}{3}x-10...(1)$

$2x+y=4...(2)$

Starting from equation (2), we will derive:

$y=4-2x...(2)$

Next, by inserting this value into equation (1), we will achieve:

$4-2x=\frac{1}{3}x-10$

After multiplying both sides by 3, we will arrive at:

$3\cdot 4-3\cdot 2x=3\cdot \frac{1}{3}x-3\cdot 10$

$12-6x=x-30$

$12-6x-x=x-x-30$

$12-7x=-30$

$12-12-7x=-30-12$

$-7x=-42$

$\frac{-7x}{-7}=\frac{-42}{-7}$

$x=6$

Now substituting this back into equation (2), we will find:

$y=4-2(6)$

$y=4-12$

$y=-8$

Thus, the solution to our specified set of equations is $(6,-8)$ .

4 0

25 days ago

Read 2 more answers

The photo shows a small coin. The scale from the actual coin to the photo is

PIT_PIT [12445]

8mm correlates to 2cm just as 8mm aligns with 20mm

The ratio of 8: 20 simplifies down to 2: 5

3.25cm ÷ 5 equals 0.65cm

Multiplying 0.65 by 2 results in 1.3cm

Your answer amounts to 1.3cm

6 0

1 month ago

Each leg of a 45°-45°-90° triangle measures 12 cm. Triangle X Y Z is shown. Angle X Y Z is a right angle and angles Y Z X and Z

babunello [11817]

Using the Pythagorean theorem: In a right triangle where legs are labeled a and b, and hypotenuse is c. Given the triangle ΔXYZ has a right angle at Y, with angles YZX and ZXY both measuring 45 degrees, and ZY = YX = 12 cm. The task is to find the length of XZ.

5 0

1 month ago

Read 2 more answers

Assume that a study of 500 randomly selected airplane routes showed that 482 arrived on time. Select the correct interpretation

babunello [11817]

Answer: C. Significant at 0.036

Step-by-step explanation:

Given:

Total samples selected Ns= 500

Airplanes that arrived on time Na = 482.

Airplanes that arrived late Nl = 500 - 482 = 18

Calculating the probability of an airplane arriving late:

P(L) = Nl/Ns

P(L) = 18/500

P(L) = 0.036

An event is deemed significant if its probability is equal to or less than 0.05.

As P(L) < 0.05

P(L) = Significant at 0.036

4 0

1 month ago