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BaLLatris
12 days ago
11

A population mean of 360, a standard deviation of 4, and a margin of error of 2.5%

Mathematics
1 answer:
AnnZ [11.9K]12 days ago
3 0

Answer:

The confidence interval is (351.04, 368.96)

Step-by-step explanation:

Given are population mean = 360

Standard deviation = 4

margin of error = 2.5% = 0.025

As the population standard deviation is known, we can apply the Z critical value

For a two-tailed critical value corresponding to 2.5%, we have

2.24

The margin of error is calculated as ±Critical value * standard deviation

= ±2.24(4)

= ±8.96

The confidence interval can be determined as follows = (Mean - margin of error, Mean + margin of error)

=(360-8.96, 360+8,.96)\\= (351.04, 368.96)

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Pablo is studying the function f(x) shown in the graph. He claims that he can transform the function to include ordered pair (2,
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Kindly present the graph.

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1 month ago
At Fairview middle school 75 band members need to raise a total for a trip of $8,250 for a trip so far they have raised $3,120 h
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8250-3120=5130

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13 days ago
Thirty-six of the staff of 80 teachers at a local intermediate school are certified in Cardio-Pulmonary Resuscitation (CPR). In
Zina [12005]

Answer:

In approximately 81 days, it is likely that the teacher on bus duty will be certified in CPR

Step-by-step explanation:

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Hence

p = \frac{36}{80} = 0.45

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45% of the time

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7 0
26 days ago
Initially 5 grams of salt are dissolved into 10 liters of water. Brine with concentration of salt 5 grams per liter is added at
Svet_ta [12314]

The salt enters at a rate of (5 g/L)*(3 L/min) = 15 g/min.

The salt exits at a rate of (x/10 g/L)*(3 L/min) = 3x/10 g/min.

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3 0
1 month ago
A. Consider the following algorithm segment: for i := 1 to 4, for j := 1 to i, [Statements in body of inner loop. None contain b
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Answer:

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for j:= 1 to i (Inner loop)

next j,

next i

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(b) In the given algorithm segment;

for i:= 1 to n, (Outer loop)

for j:= 1 to i (Inner loop)

next j,

next i

where n denotes a set of positive integers.

<pthe inner="" loop="" also="" runs="" for="" times="" and="" the="" outer="" times.=""><pthus the="" total="" iterations="" of="" inner="" loop="" for="" entire="" algorithm="" is:="">

= i × n

= "i × n" iterations

</pthus></pthe>
6 0
1 month ago
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