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aksik
1 month ago
8

What is the product of 2x2 – 3xy + y2 and 2x – 4y?

Mathematics
1 answer:
AnnZ [12.3K]1 month ago
8 0

Answer:

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

Step-by-step explanation:

Given:

Multiplication of 2x^2 – 3xy + y^2 and 2x – 4y

Multiplication refers to the product

(2x^2 – 3xy + y^2) (2x – 4y)

Expand the brackets

= 4x^3 - 8x^2y - 6x^2y + 12xy^2 + 2xy^2 - 4y^3

Combine like terms

= 4x^3 - 14x^2y + 14xy^2 - 4y^3

The result is

C. 4x^3 - 14x^2y + 14xy^2 - 4y^3

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Find the midpoint between each pair of points.<br> (-1,-5) and (-5,9)
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The work is illustrated and shown.
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16 days ago
En la figura adjunta se muestra un estuche de brocas de acero que sirven para perforar paredes de cemento. Las brocas están nume
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Respuesta:

1/16   2/16  3/16  4/16  5/16  6/16  7/16  8/16 9/16 10/16  11/16 12/16

Explicación paso a paso:

Para identificar las brocas existen dos aspectos a considerar:

1.- Las fracciones que comparten el mismo denominador aumentan en orden ascendente a medida que los numeradores incrementan, lo que significa que entre

9/16   3/16    7/16     5/16   11/16    el orden sería (de menor a mayor)

3/16     5/16     7/16     9/16     11/16

2.- Fracciones con diferentes denominadores pueden convertirse a un denominador común /16 multiplicando la fracción, por ejemplo

1/4   =  1*4/4*4   =  4/16

Aplicando este método, todas las fracciones se transforman al formato mencionado previamente y se organizan

1/4   = 4/16

3/8  = 6/16

1/2  = 8/16

5/8 =  10/16

1/8  =  2/16

Por lo tanto, hay diez brocas, comenzando con 1/16 hasta la número 12 que es 12/16

Finalmente, el orden sería:

1/16   2/16  3/16  4/16  5/16  6/16  7/16  8/16 9/16 10/16  11/16 12/16

4 0
27 days ago
Find a vector parametrization of the ellipse centered at the origin in the xy-plane that has major diameter 8 along the x-axis,
zzz [12365]

Answer:

E(t) = [ 4cos(t), 2 sin(t) ]

Step-by-step explanation:

The equation for the ellipse can be represented as:

 (x² ÷ a² ) + (y² ÷ b² ) = 1    Here, a and b symbolize the semi-major and semi-minor axes.

In this specific instance, we have    x²/16 + y²/ 4 = 1

This expression indicates that it follows the form of (x/a)² + (y/b)² =1

Specifically in our case,    x²/16  + y²/4 = 1, which resembles                 sin²α + cos²α = 1.

By setting x = 4 cos(t), we can proceed to calculate y.

Utilizing the equation x²/16  + y²/4 = 1, we find that:

x²/16  + y²/4 = 1   ⇒    (x²  +  4y²) ÷ 16  = 1

Solving for y yields: (x²  +  4y²)  = 16    ⇒  y²  = ( 16 - x²) ÷4

Substituting x = 4 cos(t) gives us y²  =  (16 - 16cos²(t)) ÷ 4, leading to y = √4 (1 - cos²(t)).

Consequently, we have y = 2 sin(t).

Thus, the vector parameterization of the ellipse can be stated as:

E(t) = [ 4cos(t), 2 sin(t) ]

3 0
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To obtain a complete response, the diagram would be essential. However, to approximate the solution, I'd calculate the distances from her home to her school and combine that with the stretch from school to work, and finally, from work back home. If there’s no information regarding the distance from work to home, I’d simply double the traveled distance already accounted for.
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23 days ago
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cynara has a bag of red, blue, and black pens. She randomly selects a pen, records the color, and puts it back in the bag, She d
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Calculate the probability of each pen color by dividing the number of times each color was chosen by the total selections:

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Blue pens: 10 out of 30, which simplifies to 1/3

Black pens: 14 out of 30, which simplifies to 7/15

To find the likelihood of first selecting a blue pen and then a red pen, multiply their individual probabilities:

(1/3) × (1/5) = 1/15

The resulting probability is 1/15.

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