When comparing prices for activities at a local recreation center, you notice that the center charges different prices on differ

Answer:

The correct options are:

The term 5x³ can be removed

The power of the first term, 5x³, can be modified to 2 and combined with the second term, 2x²

Explanation:

The degree of an expression is identified by its highest exponent.

The expression in question is:

5x³ + 2x² + 7x - 3

Observing this, we see that the highest exponent is 3, indicating that the expression’s degree is 3.

A quadratic function is defined as having degree 2, meaning the highest degree must be 2.

Thus, Martha must eliminate the term with degree 3 (5x³) from her function.

This can be achieved through two methods:

1- She can simply remove the term with the third degree.

2- She can change the term with degree 3 to a lower degree and combine it with an existing like term.

Evaluating the options, we conclude the two accurate choices are:

- The term 5x³ can be eliminated.

- The exponent on the first term, 5x³, can be reduced to 2 and subsequently joined with the second term, 2x².

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Answer:

Kindly present the graph.

Step-by-step explanation:

Assuming that the departure day for both is day 0, Sandy's next day off occurs on day 4, while Morgan's falls on day 10. Sandy's days off will be on days 4, 8, 12, 16, and 20. Meanwhile, Morgan's days off will be on days 10, 20, 30, 40, and 50. Thus, both of them will share a day off on day 20, meaning they will next have a joint day off in 20 days.

Answer:

Step-by-step explanation:

105 divided by 5 equals 21

21m=b

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Answer:

Tan(b°) = 3/4, which is equivalent to three fourths (C).

Step-by-step explanation:

Triangle JKL is a right triangle with angle K being the right angle and angle L equal to b°.

We will employ SOHCAHTOA principles from trigonometry to calculate the sides' values.

For triangle ∆JKL:

Sin(b°) = opposite/hypotenuse

Sin(b°) = 3/5

Cos(b°) = adjacent/hypotenuse

Cos(b°) = 4/5

Tan(b°) = 3/4.

From the earlier information, we have the values for each side of triangle ∆JKL.

Please refer to the attached diagram for the triangle (1).

Triangle ∆JKL is scaled with a factor of 2.

This implies multiplying each side of ∆JKL by 2, resulting in:

Opposite side = 2(3) = 6

Adjacent side = 2(4) = 8

Hypotenuse = 2(5) = 10.

To find tan(b°) for the new triangle, we use the tangent ratio:

Tan(b°) = opposite/adjacent.

Tan(b°) = 6/8.

Tan(b°) = 3/4.

Find the diagram for the new triangle included (2).

Diagram 3 provides a depiction of both triangles.

As shown, the angle remains unchanged when a triangle is scaled by a factor.

Thus, we conclude that tan(b°) = three fourths (C).