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Sati
2 months ago
8

A large offshore oil platform needs to transmit signals between different devices on the platform with high reliability and low

latency. However, they are unable to cover the platform with their existing Wi-Fi connections.What is the best solution for the platform in this scenario?
Computers and Technology
1 answer:
amid [951]2 months ago
6 0

This is about achieving a more efficient network.

The ideal solution would be to implement a private 5G connection on the platform.

  • Currently, their existing Wi-Fi connections do not suffice to cover the platform.

They now require a connection that exhibits high reliability and decreased latency.

  • Here, lower latency translates to minimal or nonexistent delays in the transmission of information, meaning it can handle a substantial amount of data very efficiently. This points to a rapid and proficient connection.

  • Since they are currently on Wi-Fi, they must upgrade to something that offers greater speed.

While 4G Wi-Fi typically functions around a frequency of 2.4GHz and a speed of  , 5G operates at approximately 30 GHz.

  • Moreover, the latency for 4G Wi-Fi hovers around 50 milliseconds, whereas 5G achieves about 1 millisecond.

  • Additionally, the speed of 5G can reach up to 20 GB per second, which is roughly 20 times faster than 4G.

Consequently, 5G clearly outpaces 4G in terms of speed and offers significantly lower latency.

The most suitable solution, therefore, is to install a private 5G connection on the platform.

Read more at; brainly.in/question/46252999

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7 0
26 days ago
Exercise 8.1.9: Diving Contest Your school is hosting a diving contest, and they need a programmer to work on the scoreboard! Yo
zubka84 [1067]

Response:

def calculate_score(theTuple):

    first, second, third = theTuple

    if first >= 0 and first <=10 and second >= 0 and second <=10 and third >= 0 and third <=10:

         print(first + second + third)

    else:

         print("Range must be 0 to 10")

Clarification:

This line initiates the function

def calculate_score(theTuple):

This line extracts the values used in the function

    first, second, third = theTuple

The subsequent if statement verifies whether the values fall within the 0 to 10 range

    if first >= 0 and first <=10 and second >= 0 and second <=10 and third >= 0 and third <=10:

This computes the total score

         print(first + second + third)

else:

Should the scores be outside the 0 to 10 limits, this line will be executed

         print("Range must be 0 to 10")

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1 month ago
According to the author, there are five hedging strategies organizations can pursue. One of them is: Select one: a. commit with
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Answer:

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Explanation:

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7 0
1 month ago
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ivann1987 [1066]

Answer:

I am crafting a Python function:

def angry_file_finder(filename): #function definition, this function takes the file name as input

with open(filename, "r") as read: #the open() function is employed to access the file in read mode

lines = read.readlines() #readlines() yields a list of all lines in the file

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There is a more efficient way to write this function without using the readlines() method.

def angry_file_finder(filename):

with open(filename, "r") as file:

for line in file:

if '!' not in line:

return False

return True

print(angry_file_finder("file.txt"))

The revised method opens the file in reading mode and directly uses a for-loop to traverse through each line to search for the "!" character. In the for-loop, the condition checks if "!" is absent from any line in the text file. If it is missing, the function returns False; otherwise, it returns True. This approach is more efficient for locating a character in a file.

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22 days ago
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