Answer:
The following C++ program is displayed below. No output is produced as per the requirements stated in the question.
#include <iostream>
using namespace std;
int main() {
// declaration and initialization of integer variables
int k, memberID = 12, nMembers=5;
bool isAMember;
// declaration and initialization of integer array
int currentMembers[] = {12, 34, 56, 78, 90};
for(k=0; k<nMembers; k++)
{
if(memberID == currentMembers[k])
{
// if the member is found in the array, the loop exits using the break statement
isAMember = true;
break;
}
else
isAMember = false;
}
return 0;
}
Explanation:
The program starts with the declaration and initialization of integer variables, followed by the definition of an array that holds the identifiers of all members.
The Boolean variable is declared, although it isn't initialized at this point.
int k, memberID = 12, nMembers=5;
bool isAMember;
int currentMembers[] = {12, 34, 56, 78, 90};
Subsequently, the array containing the members' IDs is searched for the specific member ID. This action is performed using a for loop along with an if-else condition within that loop.
If the member ID exists in the array, the variable isAMember is set to true; otherwise, it is marked as false.
If isAMember is set to true, the break statement allows for the loop to be exited early.
for(k=0; k<nMembers; k++)
{
if(memberID == currentMembers[k])
{
isAMember = true;
break;
}
else
isAMember = false;
}
The break statement is utilized since any other IDs in the array won't match the given member ID and thus, the variable isAMember would incorrectly be initialized to false even if the member ID is present in the array. Therefore, it's crucial to terminate the loop as soon as the matching member ID is located.
This program can be tested by utilizing different member ID values and varying the size of the array.
