You stand on a bathroom scale in a moving elevator. what happens to the scale reading if the cable holding the elevator suddenly

Answer:

Explanation:

Consider the following:

Length= 2L

Linear charge density=λ

Distance= d

K=1/(4πε)

The electric field measured at point P

Thus,

Now, by applying integration to the equation above

The string does not experience any force of tension, as it balances two forces acting in the same direction. Hence, the tension is zero.

Explanation:

If tension existed in the string, it would mean that two equal but opposite forces are exerting pull in contrary directions.

When a force of f newtons is applied from the right and another force of f newtons from the left, the resulting action occurs through one force. Because there is action on the same string in opposing directions, the tension in the string can only be equal to the magnitude of the string itself.

Therefore, the string indeed has no tension since it is dealing with two forces acting in the same direction. Thus, the tension is zero.

Answer:

Explanation:

Transformation of Energy

Also known as energy conversion, this refers to the process in which energy shifts from one type to another. In this context, three energy forms are involved. When the object is stationary at the ramp's peak, it possesses gravitational potential energy, calculated as

As the object descends the frictionless ramp, it converts all its potential energy into kinetic energy, represented as

Thus,

Ultimately, when the object encounters a rough surface, all energy converts to thermal energy. The work performed by the friction force corresponds to the alteration in kinetic energy, as all velocity is lost in this process:

Given the kinetic energy equals the initial potential energy:

The negative sign indicates that the work acted against the direction of movement, meaning the force and displacement are 180° apart.

This outcome is independent of the distance D needed to halt the block or the kinetic friction coefficient.

The formula used is known as the Law of Universal Gravitation. The gravitational constant G is 6.67×10⁻¹¹ Nm²/kg². The Earth's mass is <span>5.972 ×10</span>²⁴ kg. The mass of the rocket is negligible in comparison to Earth’s mass, hence it is unnecessary for our calculations. Plugging in the values:

F = (6.67×10⁻¹¹ Nm²/kg²)(5.972 ×10²⁴ kg)/(4000 miles*(1.609 km/1 mile))²
F = 9616423.08 N

The work done is given by
W = Fd
W = (9616423.08 N)(2000 miles*1.609 km/mile)
W = 9.095×10¹⁰ Joules

Answer:

 = 3289.8 m/s

Explanation:

This problem can be approached using momentum definitions.

     I = ∫ F dt

We substitute and compute.

     I = ∫ (at - bt²) dt

Integrating gives us:

      I = a t² / 2 - b t³ / 3

We will evaluate between the limits I=0 for t = 0 ms and higher I=I for t = 2.74 ms:

      I = a (2.74² / 2- 0) - b (2.74³ / 3 -0)

      I = a 3.754 - b 6.857

Substituting the values for a and b, we find:

      I = 1500 3.754 - 20 6.857

      I = 5,631 - 137.14

      I = 5493.9 N s

Next, we engage the relationship between impulse and momentum:

      I = Δp = m - m v₀o

      I = m - 0

       = I / m

     = 5493.9 /1.67

     = 3289.8 m/s