The speed resulting from the plane is (3) 226 m/s
Reasoning:
We can determine the plane's resultant speed using the Pythagorean Theorem because the two speeds form a right angle (creating a right triangle).
Thus, the computation is as follows:
Consequently, the plane's resultant speed is (3) 226 m/s
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Answer:
A) 5.1*10^10m B) 5.4*10^6m
Explanation:
Utilizing the formula for surface radiation P (energy per second in Watts) = emissivity constant * surface area * Stefan-Boltzmann constant * Temperature in Kelvin^4 *
2.7*10^31 = 1* 5.67*10^-8*A*11000^4
Rearranging to solve for A = 2.7*10^31 / (5.67*10^-8*1.46*10^16) = 0.3261*10^23m^2
Assuming the shape is spherical, the surface area is = 4πR^2 (radius of Rigel)
R = √(0.3261*10^23 / 4*π) = 5.1 * 10^10m
B) repeating the same calculation
2.1 *10^23 = 1*A*5.67*10^-8*10000^4 where A is the surface area of Procyon
Rearranging gives A = 2.1*10^23/(5.67*10^-8*10^16)
A = 0.37*10^15
Assuming the star is spherical;
A = 4πR^2 where R is Procyon's radius
R = √(0.37*10^15/4π) = 5.4*10^6m
The required lift force is approximately 866.92 N. To determine this, we first establish the shark's mass at 92 kg and its density at 1040 kg/m³. The volume of the shark is calculated by dividing mass by density, yielding 0.08846 m³. The buoyant force acting on the shark is then determined by multiplying the volume by the density of water and gravity, resulting in a lift force of 866.92 N.
Result: -50.005 kJ
Details:
Provided Data
mass of the system = 10 kg
work done = 0.147 kJ/kg
Elevation change 
initial speed 
Final Speed 
Specific internal Energy 
according to the first Law of thermodynamics
where KE represents kinetic energy
PE indicates potential energy
U denotes internal Energy
Q = 1.47 + 3.375 - 4.850 - 50
Q = -50.005 kJ
Answer:
a) The frequency is 3.191x10^11.
b) The type of radiation is microwave radiation.
c) The energy of one quantum of this radiation amounts to 1.32x10^-3ev.
Explanation:
For further details and calculations, please refer to the image below.
