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Nadusha1986
16 days ago
14

Which factor limits interference between waves? A constant phase relationship between waves Similar wave amplitudes Unequal wave

lengths Radiation through the same region
Physics
2 answers:
Ostrovityanka [2.2K]16 days ago
8 0

Answer:

waves of similar amplitude

Explanation:

When two waves propagate within the same medium and possess comparable amplitudes, their likelihood of interfering with each other in either a constructive or destructive manner diminishes. This interference arises when wave amplitudes reach a particular point in the medium from opposite directions, leading to their combination (superposition) or cancellation.

Thus, if the waves exhibit similar amplitudes, the extent of their interference will be minimized.

serg [2.5K]16 days ago
5 0

Answer:

Different Wavelengths

Explanation:

"For a stable and distinct interference pattern to form, two essential conditions must be satisfied: The wave sources need to be coherent, meaning they should produce identical waves that maintain a constant phase difference. Additionally, the waves need to be monochromatic, corresponding to a single wavelength." Therefore, disparities in wavelength will hinder the interference among the waves.

(I answered this on the quiz and received a correct score)

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Answer:

Explanation:

a

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A small cork with an excess charge of +6.0µC is placed 0.12 m from another cork, which carries a charge of -4.3µC.
serg [2593]

A) 16.1 N

The force of electricity acting between the corks can be calculated using Coulomb's law:

F=k\frac{q_1 q_2}{r^2}

where

k represents Coulomb's constant

q_1 = 6.0 \mu C=6.0 \cdot 10^{-6} C denotes the charge magnitude on the first cork

q_2 = 4.3 \mu C = 4.3 \cdot 10^{-6}C indicates the charge magnitude on the second cork

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By inserting the values into the formula, we arrive at

F=(9\cdot 10^9 N m^2 C^{-2} )\frac{(6.0\cdot 10^{-6}C)(4.3\cdot 10^{-6} C)}{(0.12 m)^2}=16.1 N

B) Attractive

<pas per="" coulomb="" law="" the="" orientation="" of="" electric="" force="" between="" two="" charged="" entities="" relies="" on="" their="" charge="" signs.=""><pmore specifically="">

- when both are similarly charged (e.g. positive-positive or negative-negative), the force is repulsive

- when charges are of opposite signs (e.g. positive-negative), the resulting force is attractive

<pin this="" case="" we="" have="">

Cork 1 holds a positive charge

Cork 2 possesses a negative charge

<pthus the="" force="" acting="" between="" them="" is="" attractive.="">

C) 2.69\cdot 10^{13}

The total charge of the negative cork is

q_2 = -4.3 \cdot 10^{-6}C

<pwe understand="" that="" a="" single="" electron="" has="" charge="" of="">

e=-1.6\cdot 10^{-19}C

<pthe total="" charge="" of="" the="" negative="" cork="" arises="" from="" having="" n="" extra="" electrons="" so="" we="" can="" express="" it="" as="">

q_2 = Ne

<pafter solving="" for="" n="" we="" can="" determine="" the="" count="" of="" excess="" electrons:="">

N=\frac{q_2}{e}=\frac{-4.3\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=2.69\cdot 10^{13}

D) 3.75\cdot 10^{13}

The overall charge on the positive cork is

q_1 = +6.0\cdot 10^{-6}C

<pthe charge="" of="" a="" single="" electron="" is="" known="" to="" be="">

e=-1.6\cdot 10^{-19}C

<pthe total="" charge="" of="" the="" positive="" cork="" results="" from="" n="" excess="" electrons="" which="" can="" be="" depicted="" as="">

q_1 = -Ne

<pby calculating="" for="" n="" we="" derive="" the="" number="" of="" electrons="" cork="" has="" lost:="">

N=-\frac{q_1}{e}=-\frac{+6.0\cdot 10^{-6} C}{-1.6\cdot 10^{-19} C}=3.75\cdot 10^{13}

</pby></pthe></pthe></pafter></pthe></pwe></pthus></pin></pmore></pas>
6 0
17 days ago
Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart
Keith_Richards [2263]

Answer:F=\frac{(M+m)g}{\mu _s}

Explanation:

Provided:

The trolley, with mass M, is allowed to roll freely without friction.

The coefficient of friction between the trolley and mass m is \mu _s.

A force F is applied to mass m.

The acceleration of the system is

a=\frac{F}{M+m}

The frictional force will counterbalance the weight of the block.

The frictional force is =\mu _sN

N=ma

\mu _sN=mg

\mu _sma=mg

\mu _s=\frac{g}{a}

F=\frac{(M+m)g}{\mu _s}

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An imaginary cubical surface of side L has its edges parallel to the x-, y- and z-axes, one corner at the point x = 0, y = 0, z
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A car rolls down a ramp in a parking garage. The horizontal position of the car in meters over time is shown below. Graph of ver
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Answer:

d_total = 12 m

Explanation:

In this kinematics scenario illustrated in the graph provided, we determine the distance traveled over a 24-second duration.

The comprehensive distance can be calculated as follows:

d_total = d₁ + d₂ + d₃

Given that d₂ on the graph is level (v=0), its distance equates to zero, hence d₂ = 0.

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For distance d₃:

d₃ = 6 - 0 = 6 m

Thus, the overall distance covered is:

d_total = 6 + 0 + 6

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23 days ago
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