Answer
Continue on your current heading and maintain your speed unless the vessel required to give way does not act.
Explanation
When two vessels approach each other, the one positioned on the right side is designated as the stand-on vessel, which means the other vessel, the give-way vessel, must yield. In this circumstance, you should keep your course and speed unless the give-way vessel fails to do so. If that happens, you must take evasive maneuvers to avoid collision by steering clear, never turning toward or crossing in front of the other vessel.
Reasoning:
Let's denote the size of a large server as L and the size of a smaller server as S.
According to the data provided, we have two equations:
2L + 4S = 64.............(1)
and
L + 3S = 40...............(2)
To solve the equations, we proceed as follows:
2(2)-(1)
2L - 2L + 6S - 4S = 2*40 - 64
2S = 16
thus, S = 8..................(3), which indicates the size of the small server
Using (3) in (2) yields
L + 3(8) = 40
L = 40 - 24 = 16..............indicating the size of the large server
The primary issue was declaring int prod within the while loop, which caused prod to reset to 1 each time the loop executed.
If a packet gets figuratively “sucked into a black hole” and is not received by the original sender, with no message returned to clarify the situation, there is an issue. This lack of communication indicates there is a problem with the _____.
A.) ICMP
B.) TCP/IP
C.) HTTP
D.) ISO
A.) ICMP
I hope this information is useful and wish you the best.
~May
num_cents = 109 if num_cents >= 100: print('Dollar or more') else: print('not a dollar')
