If hair grows at a rate of approximately 0.44 mm per day, how many

Answer:

-1

Step-by-step explanation:

The roots of the polynomial are -2 and 3. According to the zero product property:

Given that the last term in the cubic equation is -6, it indicates that a must equal 1 as the product of -2 and 3 already results in -6. This can be verified by expanding the three factors:

Thus, following the zero product property, the final value is -1.

Hope this clarifies!

The sales increased by 44.4%.

Step-by-step explanation:

• Let's calculate this cumulatively
• 90 of 10% = 9, resulting in 99
• 90 of 10% = 9, leading to 108
• 90 of 10% = 9, which becomes 117
• 90 of 10% = 9, amounting to 126
• 90 of 4% = 3.6, giving 129.6
• 90 of 0.044% = 0.0396, approaching 129.99
• This indicates an approximate 44.44 increase, affirming that there was indeed growth.
• Always begin with the first approximation rule by using 50% of 90 if the result is above 130.
• Then lower it to 40% of 90 to check if sales drop below 130.
• The approach should always commence with 50, 40, 30... 10 percentages.
• As an alternative, use 10, 1 or decimal values.
• Establish approximations using decimals and rounding up simplifies the computation.

Answer:

Step-by-step explanation:

A domain consists of the values for which a function is applicable and exhibits a graph. In this instance, the domain starts at -2 and goes up to 1.

"All real numbers from -2 inclusive to less than 1."

Note: The solution is highlighted.

import java.util.Scanner;

import java.util.Random;

public class RandomGenerateNumbers {

public static void main (String [] args) {

Random randomGenerator = new Random();

int seed = 0;

seed = 4;

randomGenerator.setSeed(seed);

System.out.println(randomGenerator.nextInt(50) + 100);

System.out.println(randomGenerator.nextInt(50) + 100);

return;

}

}

Answer:

• No, the second machine (function B) can produce an output of 0, while the first machine (function A) cannot.

Explanation

The functionality of each machine is dictated by the expression it operates under.

1)  Function A:

To achieve an output of 0 with the equation y = x² + 3, one would need to resolve the equation x² + 3 = 0.

Given that x² is always non-negative for any real number, x² + 3 will always be at least 3, meaning an output of 0 is unattainable with the first machine.

2) Function B:

By solving

Thus, utilizing x = 4 will yield an output of 0 with this machine.