Response:
Step-by-step explanation:
Assuming there are 100 sour candies, thus-
since 26% of the candies are grape, it follows that 26% of 100 candies means we have 26 grape candies
Consequently, the remaining candies that are not grape amount to 100-26 = 74
Applying the multiplication principle:
P(A ∩ B) = P(A)/ P(B|A)
Initially, there are 26 grape candies, therefore the probability of selecting the first grape candy = 26C1 = 26
After choosing the first one, we put the selected grape candy back, so there are still 100 candies total P(B|A) = 100C3 = 100 x 99 x 98 x 97!/3! X 97!
= 50 x 33 x 98
Thus, the probability becomes 1/ 50 x 33 x 98 x 26
= 1/4204200
Given the specified angles, one is 90 degrees, indicating that the triangle is a right triangle. With provided angles and one side representing the hypotenuse (the longest side), the area is determined using the formula: Area = 1/2 * base * height. Let's compute the height and base:
From sin 75, we derive height = 1.67.
And from cos 75, we obtain base = 0.45.
Calculating area gives us Area = (0.45 * 1.67) / 2, resulting in 0.37 square units.
Thus, the triangle's area is approximately 0.37 square units.
It's from Dublin to San Juan
The departure is scheduled for Friday at 1:30 PM (Dublin Time) ==> Time in San Juan is 9:30 (-4 Hours)
Travel duration is 16 Hrs (Dublin arrives on Saturday at 6:30PM) and reaching San Juan on Saturday at 9:30 +16;30 means it's 2 AM (26-24)
The equation provided in slope-intercept form is 226.50 = 7.5 (25) + 39. Step-by-step explanation: The slope-intercept form of an equation is represented by y = mx + c. The hourly cost of boat rental is $25. Assuming a one-time cleaning fee of k, and with the boat rented from 11 am to 6:30 pm, the total hours of use amount to 7.5 hours. Consequently, the rental cost for those 7.5 hours becomes 7.5 multiplied by $25, equating to $187.50. The total sum paid by the family amounts to $226.50, which equals the cleaning fee plus the 7.5-hour rate. Thus, the cleaning charge comes to $226.50 - $187.50 = $39. The equation presented reflects this relationship.
