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Marina86
3 months ago
8

The probability that Jane will go to a ballgame (event A) on a Monday is 0.73, and the probability that Kate will go to a ballga

me (event B) the same day is 0.61. The probability that Kate and Jane both go to the ballgame on Monday is 0.52. From the given scenario, we can conclude that events A and B are . NextReset
Mathematics
2 answers:
AnnZ [12.3K]3 months ago
8 0

The answer for all you Edmentum/Plato users is

dependent events because P(A and B) does not equal P(A) * P(B)

Inessa [12.5K]3 months ago
4 0

Events A and B are termed independent when

Pr(A\cap B)=Pr(A)\cdot Pr(B),

if not, events A and B are classified as dependent.

The events A, B and A∩B are:

  • A - Jane plans to attend a ballgame on Monday;
  • B - Kate intends to go to a ballgame on Monday;
  • A∩B - Both Kate and Jane will be at the ballgame on Monday.

Pr(A)=0.73,\ Pr(B)=0.61,\ Pr(A\cap B)=0.52.\\ \\ Pr(A)\cdot Pr(B)=0.73\cdot 0.61=0.4453\neq 0.52=Pr(A\cap B).

Answer: events A and B are dependent


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Answer:

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Step-by-step explanation:

The initial scenario is a specific case of the subsequent one, so we will address the second case first.

Consider y = A\sin(kt) + B\cos(kt). Through the utilization of derivatives and trigonometric function properties, it is determined that

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