Sunita bought a 10 kg box of grapes from the market. She gave 3 1/2 kg of her grapes to her friend Reena and 2 1/4 kg to Anita.

To determine the values of b that fulfill 3(2b+3)^2 = 36

we start with
3(2b+3)^2 = 36
Divide both sides by 3
(2b+3)^2 = 12
Next, take the square root of both sides
(2b+3)} = (+ /-) \sqrt{12} \\ 2b=(+ /-) \sqrt{12}-3

b1=\frac{\sqrt{12}}{2} -\frac{3}{2}
b1=\sqrt{3} -\frac{3}{2}

b2=\frac{-\sqrt{12}}{2} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}
Thus,

the solutions for b are
b1=\sqrt{3} -\frac{3}{2}
b2=-\sqrt{3} -\frac{3}{2}

Assume that the number of overdue days for the library book is X, and the total fine is Y.

Liability charges a fee of $0.30 per day for lateness,

Thus, for one day late, the fee equals: 1 * $0.30

For X days late, the fee becomes: X * $0.30.

The total fee Y corresponds to being X days late, so: Y = 0.30 * X.

Next, we'll verify which possible answers satisfy the equation Y = 0.30 * X.

Options one (-3, -0.9) and two (-2.5, -0.75) are invalid since the number of late days cannot be negative, and these give negative values for X.

Option three (4.5, 1.35) is also incorrect because the library charges per whole day; 4.5 days is not an integer, so they would charge 4 or 5 days, not 4.5.

Option four (8, 2.40) matches the equation perfectly:

Y = 0.30 * X

2.40 = 0.30 * 8

2.40 = 2.40.

Therefore, the only correct answer is option four (8, 2.40).

Dimensions of the rectangle are defined as Length=2x
Width=x
The formula for perimeter is given by 2(Length) + 2(Width).

First, we need to determine the dimensions of the rectangle, specifically its length and width.

We can derive this equation:
24=2(2x)+2(x)
4x+2x=24
6x=24
x=24/6
x=4

Consequently, Length becomes 2x, leading to 2(4)=8.

Therefore, the length is 8 inches and the width is 4 inches.

Next, we will calculate the area of the rectangle.
The area can be computed as Length multiplied by Width.

Area=(8 in)(4 in)=32 in²

Conclusion: The area of Marshall's rectangular poster is 32 in².

Answer:

1. 3.767

2. 0.145

Step-by-step explanation:

Define X as the exam scores and Y as the number of drinks.

X     Y   X-Xbar    Y-Ybar   (X-Xbar)(Y-Ybar)    (X-Xbar)²       (Y-Ybar)²    

75    5    -2.3          2.3          -5.29                      5.29              5.29

92    3     14.7         0.3           4.41                       216.09           0.09

84    2     6.7         -0.7           -4.69                     44.89             0.49

64    4     -13.3        1.3           -17.29                     176.89           1.69

64    2     -13.3       -0.7           9.31                       176.89           0.49

86    7     8.7           4.3           37.41                     75.69            18.49

81     3     3.7           0.3           1.11                         13.69             0.09

61     0    -16.3        -2.7           44.01                     265.69          7.29

73    1      -4.3         -1.7            7.31                        18.49             2.89

93    0    15.7         -2.7           -42.39                    246.49          7.29

sumx=773, sumy=27, sum(x-xbar)(y-ybar)= 33.9, sum(X-Xbar)²= 1240.1,sum(Y-Ybar)²= 44.1

Xbar=sumx/n=773/10=77.3

Ybar=sumy/n=27/10=2.7

1.

Cov(x,y)=33.9/9

Cov(x,y)=3.76667

Thus, the sample covariance of exam scores and energy drink consumption is 3.767

2.

Cor(x,y)=r=33.9/233.85553

Cor(x,y)=r=0.14496

The sample correlation coefficient for the relationship between exam scores and energy drink consumption is 0.145.

As a fraction, 2.161616 is represented as 2 161616/1000000, and when simplified, it becomes 2 10101/62500.