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Alenkinab
2 months ago
11

The linear equation 3x – 11y = 10 has

Mathematics
1 answer:
tester [12.3K]2 months ago
7 0

Answer:

Correct option: c) infinitely many solutions

Step-by-step explanation:

With an equation that contains two variables, a system having fewer equations (only one) than variables (two) leads to an infinite count of solutions.

To identify some of these solutions, one can select values for x and subsequently compute the corresponding y:

x = 0:

-11y = 10 -> y = -10/11

x = 1:

3 - 11y = 10 -> y = -7/11

x = 2:

6 - 11y = 10 -> y = -4/11

And this pattern continues.

Thus, the correct choice is c): infinitely many solutions.

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If p(x) = 5(x^2+1)+16 what is the value of p(11)
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5(122) plus 16

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p(11) equals 626
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sari has 3 times as many pencil erasers Sam. Together, they have 28 erasers.  How many erasers does Sari have
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Start by letting x represent the number of Sam's pencils. Then Sari has 3x (since she has three times as many)

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21 day ago
WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the
Inessa [12570]

Answer:

a) P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

The probability can be determined using the complement rule, with the standard normal distribution, an excel sheet, or a calculator.

P(z>1.43)=1-P(z

b) P(X

This probability can also be calculated using the normal standard distribution, an excel sheet, or a calculator.

P(z

c) P(

For this one, the probability can likewise be derived from the standard normal distribution, excel, or a calculator, with specific adjustments:

P(-1.43

Step-by-step explanation:

Previous concepts

Normal distribution refers to a symmetric probability distribution centered around the mean, indicating that occurrences near the mean are more common than those far from it.

The Z-score is a statistic that represents a value's relationship to the average of a set of values, expressed in terms of how many standard deviations it is away from the mean.

Part a

Let X denote the random variable representing the lengths within a population, and for our case, the distribution for X is as follows:

X \sim N(15,3.5)

Where \mu=15 and \sigma=3.5

We seek the probability:

P(X>20)

The most effective way to solve this is by leveraging the normal distribution and the corresponding Z-score:

z=\frac{x-\mu}{\sigma}

By applying this formula, we can find the probability:

P(X>20)=P(\frac{X-\mu}{\sigma}>\frac{20-\mu}{\sigma})=P(Z>\frac{20-15}{3.5})=P(z>1.43)

Again, this probability can be obtained either using the complement rule, the standard normal distribution, or a calculator.

P(z>1.43)=1-P(z

Part b

P(X

This probability can also be computed using either the normal standard distribution, an excel sheet, or a calculator.

P(z

Part c

P(

In this case, the probability can similarly be acquired with the help of the standard normal distribution, an excel sheet, or a calculator, with particular adjustments:

P(-1.43

5 0
1 month ago
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