The linear equation 3x – 11y = 10 has

5(x^2+8x)=14
5(x^2+8x+16)=5(x^2+8x)+5*16=5(x^2+8x)+80=14+80=94
The correct choice is the second one

Lengthwise count of 1/2-inch cubes = 8 1/2 ÷ 1/2 = 17
Widthwise count of 1/2-inch cubes = 5 1/2 ÷ 1/2 = 11
Heightwise count of 1/2-inch cubes = 2 1/2 ÷ 1/2 = 5

Total number of 1/2-inch cubes = 17 x 11 x 5 = 935

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Answer: 935 1/2-inch cubes are required.
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Step One

Deduct 32 from both sides.

F - 32 = \frac{9}{5}(k - 273.15)

Step Two

Multiply each side by \frac{5}{9}.

\frac{5}{9}(F - 32) = \frac{5}{9} \times \frac{9}{5}(k - 273.15)

\frac{5}{9}(F - 32) = k - 273.15

Step Three

Add 273.15 to both sides.

\frac{5}{9}(F - 32) + 273.15 = k

Problem B

F = 180

Solve for k

k = \frac{5}{9}(F - 32) + 273.15

k = \frac{5}{9}(180 - 32) + 273.15

k = \frac{5}{9} \times 148 + 273.15

k = 82.2222 + 273.15

k = 355.3722

k = 355.4  <<< Answer

The equation of the line through the point (5,4) with a slope of 6/5 is y = 6/5x - 2. This is determined using the linear equation format y = mx + b. By substituting in the values, you can simplify to find the y-intercept.

Answer:

The correct statements are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Since RS is parallel to DC, we conclude that;

∠BDC = ∠BRS (Angles formed on the same side of the transversal)

Furthermore;

∠BCD = ∠BSR (Angles formed on the same side of the transversal)

∠CBD = ∠CBD (Reflexive property)

Thus;

ΔBCD ~ ΔBSR by the Angle-Angle-Angle (AAA) similarity criterion.

2) Given that  ΔBCD ~ ΔBSR, we obtain;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR thus, SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

By inverting both sides we find;

BR/RD = BS/SC

3) From BR/RD = BS/SC, we apply cross multiplication;

BR/RD = BS/SC leads to;

BR × SC = RD × BS → (BR)(SC) = (RD)(BS).