If c (x) = StartFraction 5 Over x minus 2 EndFraction and d(x) = x + 3, what is the domain of (cd)(x)?

Mathematics

2 answers:

babunello [11.8K]2 months ago

8 0

Respuesta:

El dominio de la función (cd)(x) incluirá todos los valores reales de x, excepto x = 2.

Explicación paso a paso:

Las dos funciones son $c(x) = \frac{5}{x - 2}$ y d(x) = x + 3

Así que, (cd)(x) = $(\frac{5}{x - 2})(x + 3) = \frac{5(x + 3)}{x - 2}$

Por tanto, cuando x = 2, la función (cd)(x) no estará definida ya que una división por cero hará que (cd)(x) no tiene sentido.

Por lo tanto, el dominio de la función (cd)(x) abarcará todos los valores reales de x, excepto x = 2. (Respuesta)

Leona [12.6K]2 months ago

4 0

Respuesta:

la respuesta es b en edg2020

Explicación paso a paso:

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On a track and field team, 8% of the members run only long-distance, 32% compete only in field events, and 12% are sprinters onl

lawyer [12517]

Answer:

0.40

Step-by-step explanation:

The percentage of members who engage only in long-distance running is 8%

Therefore, the probability that a member focuses solely on long-distance running is P(A) = 0.08

The percentage of members who participate exclusively in field events is 32%

Thus, the probability of a member competing only in field events is P(B) = 0.32

The percentage of members acting as sprinters is 12%

So, the probability that a member is a sprinter is P(C) = 0.12

We need to determine the probability that a team member is either an exclusive long-distance runner or an only field event competitor, which equates to finding P(A or B). Since these two events cannot occur simultaneously, we can express this as:

P(A or B) = P(A) + P(B)

Substituting the known values results in:

P(A or B) = 0.08 + 0.32 = 0.40

Thus, the likelihood that a randomly selected team member runs exclusively long-distance or participates solely in field events stands at 0.40

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26 days ago

Explain how you can determine the number of real number solutions of a system of equations in which one equation is linear and t

babunello [11817]

Answer:

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