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Tju
4 days ago
10

Marcus states that the polynomial expression 3x3 – 4x2y + y3 + 2 is in standard form. Ariel states that it should be y3 – 4x2y +

3x3 +2. Explain which student is correct and why.
Mathematics
2 answers:
lawyer [4K]4 days ago
8 0

Answer: Both students are correct since Marcus presents the x variable with exponents arranged in descending order from the highest to the lowest degree. Ariel arranges the y variable similarly, from the highest to the lowest degree.

Step-by-step explanation:

PIT_PIT [3.9K]4 days ago
8 0

Answer:

Both students are accurate as Marcus has arranged the exponents of the x variable in decreasing order from the greatest to the least power. Meanwhile, Ariel has organized the exponents of the y vector in a similar descending manner from the highest to the lowest degree.

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Find three solutions for the linear equation 4x −3y = 1, and plot the solutions as points on a coordinate plane.
lawyer [4008]

Answer:

(1, 1), (2, 2.333) and (3, 3.666).

Step-by-step explanation:

To solve this equation, we can select various values for x and then compute the corresponding y values.

<pFor instance, when x = 1, we find:

4*1 - 3y = 1

3y = 3

y = 1

When x = 2, we discover:

4*2 - 3y = 1

3y = 7

y = 2.333

Then for x = 3, we have:

4*3 - 3y = 1

3y = 11

y = 3.666

Therefore, the coordinates we will plot are (1, 1), (2, 2.333), and (3, 3.666).

Refer to the attached image for the plot.

4 0
3 days ago
A CD has a 5% chance of being a smash hit and profiting $5.2 million, a 50% chance of being a modest success and profiting $0.9
Zina [3914]

P(S) = Probability of Smash = 0.05 (5%)
P(M) = Probability of Modest = 0.5 (50%)
P(F) = Probability of Flop = 0.45 (45%)
Based on this, we utilize the model for discrete random variables, leading to:
E(X) = (0.05 * 5.2) + (0.5 * 0.9) + (0.45 * 0)
= 0.26 + 0.45 + 0
= 0.71 Mill'

5 0
7 days ago
There are 345 students at a college who have taken a course in calculus, 212 who have taken a course in discrete mathematics, an
AnnZ [3877]

Answer:

There are 369 students who enrolled in either calculus or discrete mathematics.

Step-by-step explanation:

I'll create a Venn diagram to illustrate these figures.

Let’s define:

A represents the count of students who completed calculus.

B stands for those who took discrete mathematics.

We have the following:

A = a + (A \cap B)

Here, a denotes the students who studied calculus exclusively, while A \cap B represents those who took both subjects.

Using the same reasoning:

B = b + (A \cap B)

There are 188 students taking both calculus and discrete mathematics.

This implies that A \cap B = 188

A total of 212 students studied discrete mathematics.

<pBased on this, B = 212

345 students have attended a calculus course.

<pSo, from this information, A = 345

We find the total number of students who took either calculus or discrete mathematics.

(A \cup B) = A + B - (A \cap B) = 345 + 212 - 188 = 369

A total of 369 students participated in either calculus or discrete mathematics.

4 0
10 days ago
James knows that when h walks, he takes about 120 steps per minute and that each step is 2.75 feet long. Which calculation is mo
babunello [3635]

Answer:

120*2.75*60/5280

= 3.75

Step-by-step explanation:

Considering James takes 120 steps in a minute, with 60 minutes in an hour and a mile consisting of 5,280 feet, we can establish his walking pace. By multiplying his steps per minute by the distance of each step (120 * 2.75), we determine the distance he covers in one minute. This value is then multiplied by 60 to account for the total hour. Finally, the total distance is divided by the feet in a mile (5,280), which results in a speed of 3.75 miles per hour. Thus, the calculation becomes 120*2.75*60/5280

4 0
2 days ago
Read 2 more answers
How many different letter permutations, of any length, can be made using the letters M O T T O (For instance, there are 3 possib
tester [3916]

Answer:

89

Step-by-step explanation:

Given that

2 O, 2 T and 1 M

Now based on this, the following arrangements exist  

1

Three arrangements i.e. {M,T,O}

2

XX or XY

XX in 2C1 = two arrangements i.e. {OO or TT}

XY in 3C2 × 2! = six arrangements

3

XXY or XYZ

XXY in 2C1 × 2C1 × 3! ÷ 2! = twelve arrangements

XYZ in 3C3 × 3! = six arrangements

4

XXYY or XXYZ

XXYY = 4! ÷ (2! × 2!) = six arrangements

XXYZ in 2C1 ×  4! ÷ 2! = twenty four arrangements

5

= 5! ÷ (2! ×2!)

= 120 ÷ 4

= 30

Thus, the overall total is

= 3 + (2 +6)+ (12 +6) + (6 +24) + 30

= 89

5 0
7 days ago
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