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horrorfan
4 days ago
10

Given f(x) and g(x) = f(x) + k, look at the graph below and determine the value of k. k = ______ Graph of two lines. f of x equa

ls 1 over 3 x plus 2 and g of x equals 1 over 3 x plus 5
Mathematics
1 answer:
lawyer [4K]4 days ago
7 0

Solution:

We know, g(x) = f(x) + k --------(1)

It is given that f(x) = \frac{1}{3}(x+2)

and g(x) = \frac{1}{3}(x+5)

Substituting f(x) and g(x) into equation (1):

→ \frac{1}{3}(x+5) = \frac{1}{3}(x+2) + k

→ \frac{1}{3}[x+5-x-2] = k

→ k = \frac{1}{3} \times 3=1

Thus, the value of k is 1.

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243.875 to nearest tenth, hundredth, ten, and hundred
Inessa [3907]
When rounding 243.875: to the nearest tenth, it becomes 243.9; to the nearest hundredth, it is 243.88; to the nearest ten, it rounds down to 240; and to the nearest hundred, it rounds down to 200. The general rule in rounding states that if the decimal is less than 5, the number remains the same; if it is 5 or more, you round up.
8 0
2 days ago
Fourteen runners in a marathon had these race times, in hours,
AnnZ [3877]

Answer:

Attached is the histogram illustrating the marathon runners’ times.

Step-by-step explanation:

The provided data is as follows;

2.21

2.25

2.76

3.1

3.3

3.5

3.6

3.77

3.8

4.23

4.25

4.25

4.6

4.9

From this data, we can determine;

The count of runners finishing between 0 and 1 hour = 0

The count of runners finishing between 1 and 2 hours = 0

The count of runners finishing between 2 and 3 hours = 3

The count of runners finishing between 3 and 4 hours = 6

The count of runners finishing between 4 and 5 hours = 5

Based on these frequencies across the various time ranges, the histogram for the provided data has been constructed and is attached.

7 0
1 day ago
Student researchers Haley, Jeff, and Nathan saw an article on the Internet claiming that the average vertical jump for teens was
tester [3916]

Answer:

At the α = 0.10 level, there is no substantial evidence indicating that the average vertical jump for students at this school differs from 15 inches.

Step-by-step explanation:

A hypothesis test is necessary to verify the assertion that the average vertical jump of students diverges from 15 inches.

The null and alternative hypotheses are:

H_0: \mu=15\\\\H_a: \mu\neq15

The significance level is set at 0.10.

The sample mean recorded is 17, and the sample standard deviation is 5.37.

The degrees of freedom are calculated as df=(20-1)=19.

The t-statistic is:

t_{19}=\frac{M-\mu}{s_M/\sqrt{n}} =\frac{17-15}{5.37/\sqrt{20}}=\frac{2}{5.37/4.47} =2/1.20=1.67

The two-tailed P-value corresponding to t=1.67 is P=0.11132.

<pSince this P-value exceeds the significance level, the result is not significant. Therefore, the null hypothesis remains unchallenged.

At the α = 0.10 level, there is no compelling evidence that the average vertical jump of students at this school deviates from 15 inches.

7 0
6 days ago
Max rides his scooter toward Kim and then passes her at a constant speed. His distance in feet, d, from Kim t seconds after he s
tester [3916]
Max's initial distance from Kim
Max's consistent velocity
5 0
7 days ago
Read 2 more answers
At a small coffee shop, the distribution of the number of seconds it takes for a cashier to process an order is approximately no
Leona [4166]

Answer:

The correct answer is;

A. 0.17

Step-by-step explanation:

Here are the provided details;

The average time taken for a cashier to handle an order, μ = 276 seconds

The deviation from the average, σ = 38 seconds

The z-score for an order processing time of x = 240 seconds can be calculated as follows;

Z=\dfrac{x-\mu }{\sigma }

Thus;

Z=\dfrac{240-276 }{38 } \approx  -0.9474

The resulting probability

P(z = -0.9474) = 0.17361

Hence, the estimated proportion of orders processed in under 240 seconds is roughly 0.17361 or 0.17 when rounded to two decimal places.

8 0
15 days ago
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