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mel-nik
1 month ago
7

Cuantos paquetes de 10 vasos ocupo para empacar 1367 vasos

Mathematics
1 answer:
PIT_PIT [12.4K]1 month ago
8 0
137 paquetes de vasos, aunque el último solo tiene 7 vasos, es necesario para asegurar que no queden sin empacar.
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What is the coefficient in the expression shown? 42+2c
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There exist two coefficients: one pertains to x raised to the first degree, and another corresponds to the zeroth degree of x (the constant term).

Thus:
the coefficient for the constant term is 42 (i.e. 42x^0=42).
the coefficient for the linear term is 2 (i.e. 2x^1=2x)
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The table below shows the linear relationship between the number of people at a picnic and the total cost of the picnic. Which s
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The count of people serves as the independent variable. The picnic's starting cost (initial fee) is $40. When more people attend, the picnic's overall expense rises. 
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Justin wants to buy plants for his property, and he can afford to spend at most $480. The local nursery sells holly bushes for $
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Answer: 10 holly bushes and 12 bayberry shrubs

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The scatterplot below shows the shoe sizes of students and the number of books the students collected for the library book drive
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Explicación paso a paso:

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23 days ago
How many solutions does the equation sin(5x) = 1/2 have on the interval (0, 2PI]
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Answer:

Step-by-step explanation:

Considering the equation

Sin(5x) = ½

5x = arcSin(½)

5x = 30°

Then,

The general formula for sin is

5θ = n180 + (-1)ⁿθ

Dividing throughout by 5

θ = n•36 + (-1)ⁿ30/5

θ = 36n + (-1)ⁿ6

The solution range is

0<θ<2π which means 0<θ<360

First solution

When n = 0

θ = 36n + (-1)ⁿθ

θ = 0×36 + (-1)^0×6

θ = 6°

When n = 1

θ = 36n + (-1)ⁿ6

θ = 36-6

θ = 30°

When n = 2

θ = 36n + (-1)ⁿ6

θ = 36×2 + 6

θ = 78°

When n =3

θ = 36n + (-1)ⁿ6

θ = 36×3 - 6

θ = 102°

When n=4

θ = 36n + (-1)ⁿ6

θ = 36×4 + 6

θ = 150

When n=5

θ = 36n + (-1)ⁿ6

θ = 36×5 - 6

θ = 174°

When n = 6

θ = 36n+ (-1)ⁿ6

θ = 36×6 + 6

θ = 222°

When n = 7

θ = 36n + (-1)ⁿ6

θ = 36×7 - 6

θ = 246°

When n =8

θ = 36n + (-1)ⁿ6

θ = 36×8 + 6

θ = 294°

When n =9

θ = 36n + (-1)ⁿ6

θ = 36×9 - 6

θ = 318°

When n =10

θ = 36n + (-1)ⁿ6

θ = 36×10 + 6

θ = 366°

When n = 10 surpasses the θ range

Thus, the solutions range from n =0 to n=9

Therefore, there are 10 solutions within the interval 0<θ<2π

4 0
27 days ago
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