One square has an area that is 10 cm2 larger than another. What is a reasonable domain for the area of the larger square?
2 answers:
Answer:
reflects the required domain.
Step-by-step explanation:
We have two squares provided
Let the area of the larger square be denoted as x
The area of the smaller square is given, and we need to determine the domain for the larger square's area.
The domain refers to the possible values that x can assume in a function
In this context, x represents the area of the larger square
Because the area of the smaller square is
The area of the larger square must exceed
The domain will consist of all real numbers greater than 10
Mathematically, indicates the required domain.
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Answer:
15.6
Step-by-step explanation:
- Insert 39/4: 39/4 ÷ 5/8
- 39/4 ÷ 5/8 = 39/4 × 8/5
- 39/4 × 8/5 = 312/20
I hope this information is helpful!
Response:
If there are "p" pounds of peanuts and "m" pounds of a mixture containing '20% peanuts and 80% almonds', then we can formulate the following equations:
p + m = 10 -----------(1) and
4m/5 = 4 ------------(2)
The solution yields 5 lb peanuts and 5 lb mixture.
Detailed explanation:
In the mixture that Delaney desires to create, there will be
lb
= 6 lb of peanuts
Thus, there will be (10 - 6) lb
= 4 lb of almonds
If Delaney has "p" pounds of peanuts and "m" pounds of the '20% peanuts and 80% almonds' mixture, then based on the problem statement,
p + m = 10 -----------(1) and
4m/5 = 4 ------------(2)
From equation (2), we derive
m = 5 --------------(3)
From (1) and (3), we find that
p = (10 - 5) = 5