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4 days ago

Solve 3x+11= k for x.

Mathematics

2 answers:

zzz [4K]3 days ago

6 0

Answer: the correct choice is (D) $x=\dfrac{k-11}{3}.$

Step-by-step explanation: We need to determine the value of x from the following equation:

$3x+11=k~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

To find x, we should isolate x on one side and move all other terms to the opposite side of the equation.

The process of solving equation (i) is illustrated as follows:

$3x+11=k\\\\\Rightarrow 3x=k-11\\\\\Rightarrow x=\dfrac{k-11}{3}.$

Consequently, the value of x we seek is $x=\dfrac{k-11}{3}.$

Option (D) is the correct answer.

Zina [3.9K]3 days ago

3 0

x =k − <span>11 divided by 3
This resolves your issue.</span>

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You are visiting a rainforest, but unfortunately,your insect repellent has run out. As a result, at each second, a mosquito land

tester [3916]

Answer:

Step-by-step explanation:

The probability that a mosquito lands on your neck per second is 0.5

The chance of it biting once it lands is 0.2

The likelihood that it does not bite after landing is 0.8

Therefore, the probability of a bite in one second is $0.5(0.2) = 0.01$

This translates to a 1/100 likelihood of being bitten in just one second

Over the course of 100 seconds, the expected number of bites is $=1$

The anticipated interval between bites is 100

6 0

15 hours ago

Suppose the coordinate of a is 0, ar = 5, and at =7. What are the possible coordinates of the midpoint of rt ?

Zina [3914]

Here, 'a' relates to 0.

There are two scenarios for 'r' and 't'.

Scenario 1.

Both are positioned on the same side to the right of 'a'.

In this case, 'r' would equal 5, and 't' would equal 7.

The midpoint between 'r' and 't' is $\frac{5+7}{2} =6$ .

Scenario 2.

If both are found to the left of 'a'.

Then 'r' would equal -5, while 't' would equal -7.

The midpoint is $\frac{-7-5}{2} =-6$ .

Scenario 3.

If 'r' is right of 'a' and 't' is left of 'a'.

Thus 'r' equals 5 and 't' equals -7.

The midpoint is $\frac{-7+5}{2}=-1$ .

Scenario 4.

If 'r' is left of 'a' while 't' is right of 'a'.

In this case, 'r' corresponds to -5 and 't' corresponds to 7.

The midpoint is $\frac{-5+7}{2}=1$ .

The potential midpoint coordinates for 'rt' are 6, -6, 1, and -1.

4 0

1 day ago

How to write 600,000+80,000+10 in word form

tester [3916]

In numerical format, this value is represented as 680,010.
In expanded notation, it can be expressed as
600,000 + 80,000 + 10

When written in words, it is described as
Six hundred eighty thousand and ten .

Take into account that the arrangement of the numbers corresponds to each of the forms presented

Six hundred thousand equals 600,000
Eighty thousand equals 80,000
Ten equals 10

3 0

7 days ago

Two window washers start at the heights shown. (A: 21 ft high rising 8 in per second. The other is 50 feet high descending 11inc

Leona [4166]

To address this problem, let's start by formulating the general motion equation along the vertical direction.

This gives us:

$h = \frac {1} {2} gt ^ 2 + vo * t + h0$

Where,

g: gravitational acceleration
vo: initial velocity
h0: starting height

For the first individual:

$h1 = \frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21$

For the second individual:

$h2 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50$

When both individuals reach the identical altitude, the following holds:

$h1 = h2\\$

$\frac {1} {2} gt ^ 2 + \frac {8} {12} * t + 21 = \frac {1} {2} gt ^ 2 - \frac {11} {12} * t + 50$

Rearranging results in:

$\frac {8} {12} * t + 21 = - \frac {11} {12} * t + 50$

$\frac {8} {12} * t + \frac {11} {12} * t = 50 - 21$

$\frac {19} {12} * t = 29$

Solving for time:

$t = 29 (\frac {12} {19})\\t = 18.31s$

Result:

The two window washers reach the same height after 18.31 seconds.

6 0

16 days ago

Read 2 more answers

Thirty-four college students were asked how much money they spent on textbooks for the current semester. Their responses are sho

lawyer [4008]

Answer:

(a) The data point that is considered an outlier is $810.

(b) The distribution regarding expenditures on textbooks among the 34 students is right skewed.

Step-by-step explanation:

The provided data regarding how much 34 college students spent on textbooks is:

S = {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280, 290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

(a)

An outlier is defined as a value significantly different from the rest of the dataset, being either excessively high or low.

A widely-used approach for identifying outliers involves:

Identifying values that fall below Q₁ - 1.5 IQR as outliers.
Identifying values that exceed Q₃ + 1.5 IQR as outliers.

In our case,

Q₁ = first quartile

Q₃ = third quartile

IQR = Interquartile range = Q₃ - Q₁.

The first quartile value corresponds to more than 25% of the data points. It can be found by examining the median of the first half of the data.

Calculate the first quartile with the set below:

Initial half of data: {120, 130, 130, 140, 150, 150, 160, 170, 180, 210, 220, 230, 240, 250, 260, 280, 280}

This subset contains 17 values.

The median in an odd-sized dataset is the central point.

The central value here is: 180

Thus, the first quartile is Q₁ = 180.

The third quartile value corresponds to more than 75% of the data points.

We determine the third quartile from the second half of the data:

Final half of data: {290, 290, 290, 310, 320, 320, 370, 380, 390, 410, 440, 450, 470, 510, 530, 620, 810}

The median of an odd dataset serves as the middle value.

The central point is: 390

Hence, the third quartile is Q₃ = 390.

Calculate the interquartile range as follows:

IQR = Q₃ - Q₁

= 390 - 180

= 210

Next, we compute the value of [Q₁ - 1.5 IQR]:

$Q_{1}-1.5\ IQR =180-(1.5\times 210)=-135$

And then we compute [Q₃ + 1.5 IQR]:

$Q_{3}+1.5\ IQR =390+(1.5\times 210)=705$

There are no values below [Q₁ - 1.5 IQR]. However, one value exceeds [Q₃ + 1.5 IQR].

X = 810 > [Q₃ + 1.5 IQR] = 705

Consequently, the outlier identified within the dataset is $810.

(b)

A distribution is classified as positively skewed or right-skewed when the majority of the data congregates on the lower end of the spectrum.

The stem plot indicates that most of the data values are concentrated on the left side, confirming that the distribution is indeed right skewed.

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5 0

17 days ago