Can someone help me with this?1⁵ + 5² / 25⁰ - 5¹=​

Response:- 0.8/8+x=5/100

Detailed explanation:

Response:

  a. height of the pyramid: 5√7 cm

  b. overall area: (100 +200√2) cm²

  c. volume: (500/3)√7 cm³

Step-by-step explanation:

b) Each triangular face is an isosceles triangle with a base measuring 10 cm and a side length of 15 cm. That side length serves as the hypotenuse of the right triangle formed when an altitude is drawn. The altitude length can be calculated using the Pythagorean theorem as...

  h = √(15² -5²) = √200 = 10√2... cm

The lateral area equals the combined area of the four triangular faces, each one having this altitude and a base of 10 cm

  LA = 4 × (1/2)bh = 2bh

  LA = 2(10 cm)(10√2 cm) = 200√2 cm²

Additionally, the area of the square base is calculated as...

  A = s² = (10 cm)² = 100 cm²

Thus, the total surface area of the pyramid can be expressed as...

  A + LA = (100 +200√2) cm².... overall surface area

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a)  The altitudes of opposite triangular faces along with a line drawn across the center of the base form another isosceles triangle. The height of this triangle corresponds to the pyramid's height. This height can also be derived with the Pythagorean theorem.

The altitude of the face acts as the hypotenuse of the right triangle, with half the base width being one side. The other side equates to the pyramid's height.

  height = √((10√2)² -5²) = √175 = 5√7

The pyramid's height is 5√7 cm.

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c) The volume is determined using the formula...

  V = (1/3)Bh

where B represents the base area (100 cm²) determined earlier, and h stands for the height (5√7 cm) calculated in section (a).

  V = (1/3)(100 cm²)(5√7 cm) = (500/3)√7 cm³.... pyramid volume

Since the ball achieves a peak height of 18 meters at 1 second, it will begin descending thereafter. Therefore, we anticipate that the height will drop below 18 m after 1.5 sec.

f(x) = –10x2 + 20x + 8
f(x) = –10(1.5^2) + 20(1.5) + 8
f(x) = 15.5 m

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The tension does not approach infinity.
<span>Let's analyze free body diagrams (FBDs) for each mass, considering the direction of motion of m₁ as positive.

For m₁: m₁*g - T = m₁*a

For m₂: T - m₂*g = m₂*a

Assuming a massless cord and pulley without friction, the accelerations are the same.

From the second equation: a = (T - m₂*g) / m₂

Substitute into the first:
m₁*g - T = m₁ * [(T - m₂*g) / m₂]
Rearranging:
m₁*g - T = (m₁*T)/m₂ - m₁*g
2*m₁*g = T * (1 + m₁/m₂)
2*m₁*m₂*g = T * (m₂ + m₁)
T = (2*m₁*m₂*g) / (m₂ + m₁)
Taking the limit as m₁ approaches infinity:
T = 2*m₂*g

This aligns with intuition since the greatest acceleration m₁ can have is -g. The cord then accelerates m₂ upward at g while gravity acts downward, leading to a maximum upward acceleration of 2*g for m₁.</span>

The solution is 20 days, found as follows:
Each of the three friends initially makes 4 bags of dough. After 10 days, each of these bags is split into 4 new bags:
3 friends × 4 bags = 12 bags, and 12 bags × 4 = 48 bags
Then in the following 10 days, 48 bags are again divided into 4 bags each:
48 × 4 = 192 bags
Adding the periods: 10 days + 10 days = 20 days
Therefore, 192 bags are created after 20 days.